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lorasvet [3.4K]
3 years ago
12

What is the frequency of light with a wavelength of 7.9 x 10^-9 m? ( the speed of light is 3.00 x 10^8)

Physics
1 answer:
nlexa [21]3 years ago
3 0
Using the formula v=f times lambada
then v=the speed of light.
and f=what’s we’re looking for
and lambada=the wavelength.

so then you sub what you have (v and lambada) in the formula.
then multiply the frequency(f) by the given wavelength and then solve for f

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Spiderman has a mass of 80 kg. He knows his webbing will break if it is exposed to a 200 N force. What is the maximum height he
likoan [24]

Answer:

This depends on the writers

if they want they can make spiderman deny the laws of nature

8 0
3 years ago
After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 48.0 cm . The explorer finds that
Ber [7]

Answer:

g = 12.22 m/s²

Explanation:

The time period of this pendulum is given as follows:

T = \frac{time\ taken}{no. of cycles}\\\\T = \frac{144\ s}{93}\\\\T = 1.55\ s

but the formula for the time period of a simple pendulum is as follows:

T=2\pi \sqrt{\frac{l}{g}}\\

where,

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Therefore,

1.55\ s=2\pi \sqrt{\frac{0.48\ m}{g}}\\\\\sqrt{g} = 2\pi \sqrt{\frac{0.48\ m}{1.55\ s}}\\\\g = 3.49^{2}\\

<u>g = 12.22 m/s²</u>

6 0
3 years ago
The element lithium has two stable isotopes, Li-6 and Li-7. How do the atomic structures of these two isotopes compare?
Mumz [18]
All isotopes of Li have 3 protons and 3 electrons, but isotopes different in # of neutrons. Li-7 means the nucleus has 3 protons + 4 neutrons = 7 atomic mass.
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6 0
3 years ago
The kinetic energy of an object depends on two factors, ___, and ___. HINT: Remember comparing the kinetic energy of the marble
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7 0
3 years ago
Read 2 more answers
Use the chart to determine the half-life of carbon-14
lubasha [3.4K]

The correct answer to the question is B) 5,700 years.

EXPLANATION:

Before going to answer this question, first we have to understand half life period of a radio active substance.

The half life period [\ T_{1/2}\ ] of a radio active substance is defined as the time in which half of the radio active specimen has undergone decay.

As per the question, the initial concentration of the radioactive carbon-14 is given as 10,000.

Hence, initial concentration N_{0} =\ 10,000.

After 5,700 years, the remaining radio active specimen is 5000. It means that half of the radio active specimen has undergone decay in 5,700 years.

Hence,  half life period of the radio active carbon-14 specimen is 5,700 years.

7 0
3 years ago
Read 2 more answers
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