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4 years ago

What is the formula to find Average speed??

Physics

1 answer:

andreyandreev [35.5K]4 years ago

4 0

Speed is distance divided by time (s = d/t)

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A 920 kg cannon fires a 3.5 kg shell at initial acceleration of 95 m/s^2. What is the cannon's recoil force?

Mice21 [21]

Answer:

The cannon recoils with a force of 332.5 N

Explanation:

By Newton's third law Recoil force on cannon = Force in shell.

Force in shell = Mass of shell x Acceleration of shell

Mass of shell = 3.5 kg

Acceleration of shell = 95 m/s²

Force in shell = 3.5 x 95 = 332.5 N

Recoil force on cannon = 332.5 N

So, the cannon recoils with a force of 332.5 N

3 0

3 years ago

A ball whose mass is 0.4 kg hits the floor with a speed of 8 m/s and rebounds upward with a speed of 6 m/s. Collapse question pa

Colt1911 [192]

Answer:

The the average magnitude of the force exerted on the ball by the floor $11.2 \times 10^{3}$ N

Explanation:

Given:

Mass of ball $m = 0.4$ kg

Initial speed $v_{i} = -8 \frac{m}{s}$

Rebound speed $v_{f} = 6 \frac{m}{s}$

Contact time interval $\Delta t = 0.5 \times 10^{-3}$ sec

For finding the average magnitude of the force on the ball by the floor is given by,

$F_{avg} = \frac{\Delta P}{\Delta t}$

Here $\Delta P = m (v_{f}- v_{i} )$

$F_{avg} = \frac{m (v_{f} -v_{i} )}{\Delta t}$

$F_{avg} = \frac{0.4 \times (6 -( -8 ) )}{0.5 \times 10^{-3} }$

$F_{avg} = 11.2 \times 10^{3}$ N

Therefore, the the average magnitude of the force exerted on the ball by the floor $11.2 \times 10^{3}$ N

6 0

3 years ago

Read 2 more answers

Which is greater, the gravitational force between earth and the moon, or the force between earth and the sun?

Karo-lina-s [1.5K]

Earth and the Sun
GF = 3.647x10^22 N

8 0

4 years ago

find the coefficient of kinetic friction for a 10 kg box being dragged steadily across the surface with a force of 2.0 Newtons

Mazyrski [523]

Answer:

0.02

Explanation:

Force, $F=\mu_k N$ where N is normal reaction and coefficient of kinetic friction is $\mu_k$ . Also, N is equivalent to mg ie N=mg where m is mass of an object and g is acceleration due to gravity. Making $\mu$ the subject of the formula then

$\mu_k=\frac {F}{mg}$

Substituting F with 2 N, m with 10 kg and g with 9.81 then

$\mu_k=\frac {2}{10\times 9.81}=0.0203873598369\approx 0.02$

5 0

4 years ago

A cat runs 6m in 4seconds what is it speed

gayaneshka [121]

Explanation:

<h2>expation!!!!!!!!!!!!!!!!!!!!!!!!!! $$!!!!!!!!!!!!!!! explantion bbbnb</h2>

6 0

3 years ago