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ale4655 [162]
3 years ago
5

Toy car in a science experiment covers 1.6 meters in half a second. If a the car travels at a steady speed, how far will it go i

n 10 seconds? A.. 0.8 m B.. 8 m C. 16 m D. 32 m
Physics
1 answer:
Tanzania [10]3 years ago
3 0
The answer is D. 32 m.

The simple equation that connects speed (v), time (t), and distance (d) can be expressed as:
v= \frac{d}{t}         ⇒ d=v*t

It is given:
v =  \frac{1.6m}{0.5s} = \frac{1.6m*2}{0.5s*2}= \frac{3.2m}{1s}  = 3.2 m/s
t = 10 s
d = ?

So:
d= v*t=3.2m/s*10s = 32m
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Anna [14]
The answer is c. I hope it’s clear

4 0
3 years ago
A high-speed drill rotating ccw at 2400 rpm comes to a halt in 2.5 s. What is the magnitude of the drill’s angular acceleration?
WARRIOR [948]

Answer:

The magnitude of the drills angular acceleration is -32\pi s^{-2}.

The drill makes 50 revolutions before it stops.

Explanation:

The revolutions that the drill makes in 1 second is

\dfrac{2400\:rev}{60s} =40\:rev/s

And the angular velocity is

\omega= \dfrac{40 (2\pi )}{1s}          (<em>one revolution is </em>2\pi<em> radians)</em>

\boxed{\omega =80\pi\:s^{-1}}

Now, the drill comes to a halt in 2.5 s, which means the magnitude of it's angular acceleration is

a= \dfrac{\Delta \omega}{\Delta s}

a=\dfrac{80\pi-0 }{0-2.5s}

\boxed{a=-32\pi \:s^{-2}}

In other words, the magnitude of the angular acceleration is -32\pi\: s^{-2}.

Now, we find the angular displacement of the drill which is given by the equation

\theta = \omega t +\dfrac{1}{2} \alpha t^2

putting in \omega = 80\pi s^{-1}, \alpha = -32\pi s^{-2}, and t=2.5s, we get:

\theta = (80\pi s^{-1} *2.5s)+\dfrac{1}{2} (-32\pi s^{-2})(2.5s)^2

\theta = 100\pi

which is

\dfrac{100\pi }{2\pi } =50\:rev                <em>(one revolution is </em>2\pi<em> radians)</em>

50 revolutions.

In other words ,the drill makes 50 revolutions before it stops.

3 0
3 years ago
Describe how the shape of the coast may influence an incoming wave. Explain using key terms such as reflection off the shape of
frez [133]

Answer:

Describe how the shape of the coast may influence an incoming wave. Explain using key terms such as reflection off the shape of the coast and reflection of incoming waves.​

Explanation:

Describe how the shape of the coast may influence an incoming wave. Explain using key terms such as reflection off the shape of the coast and reflection of incoming waves.​

6 0
3 years ago
O
lbvjy [14]

Hi there!

1.

The period of a pendulum can be calculated using the following equation:
\large\boxed{T = 2\pi \sqrt{\frac{L}{g}}}

T = period (s)

L = length of string (m)
g = acceleration due to gravity (m/s²)

Plug in the values:

T = 2\pi \sqrt{\frac{4}{9.8}} = \boxed{4.014 s}

2.

Calculate the period:


T = \frac{\text{Time}}{\# of oscillations} = \frac{5}{20} = \boxed{0.4 s }

Frequency is the reciprocal of the period, so:


f = \frac{1}{T} = \frac{1}{0.4} = \boxed{2.5 Hz}

6 0
3 years ago
Which statement about energy transfer in a wave is true?
DIA [1.3K]
<span>energy moves between the particle of the medium</span>
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3 years ago
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