(a) As the car is moving with constant velocity, it means the rate change of velocity does not change, therefore the average acceleration of the car is zero.
Thus, there is no acceleration, when velocity is constant.
(b) Average acceleration,
Here, v is final velocity and u is the initial velocity and 
is the time interval.
As twelve seconds later, the car is halfway around the track and traveling in the opposite direction with the same speed, therefore
Thus, the average acceleration of the car is 
in the direction to the left.
Answer:
17.565 kgm/s
Explanation:
Momentum = mass × velocity
I = mv..................... Equation 1
But we can calculate the value of v using the equation of motion under gravity.
v² = u²+2gs............. Equation 2
Where u = initial velocity, s = maximum heigth, g = acceleration due to gravity.
Given: u = 0 m/s (at the maximum heigth), s = 7.0 m.
Constant: g = 9.8 m/s²
Substitute these values into equation 2
v² = 0²+ 2×7×9.8
v² = 137.2
v = √137.2
v = 11.71 m/s.
Also given: m = 1.50 kg
substitute these values into equation 1
Therefore,
I = 1.5×11.71
I = 17.565 kgm/s
Answer:
4.3 x 10^16 kg
Explanation:
M = rv^2/G =[90,000 x 5.66^2] / [6.67 x 10^-11]
M = 43,226,446,776,611,694 = 4.3 x 10^16 kg - Ida's mass.
Answer:
option B
Explanation:
An Object that has linear Kinetic energy so, it must be moving.
Expression of Kinetic energy
From the expression above we can clearly see that Kinetic energy is directly proportional to velocity of the object.
If the body has kinetic energy so, it must be moving with certain velocity.
Hence, the correct answer is option B
Answer:
3 seconds
Explanation:
To solve this problem, we have to find the acceleration of the car.
Acceleration is given as:
a = (v - u) / t
Where v = final velocity
u = initial velocity
t = time taken.
From the question,
u = 0 m/s
v = 31 mph = 13.86 m/s
t = 1.5 seconds
Acceleration, a, will be:
a (13.86 - 0) / 1.5
a = 13.86 / 1.5
a = 9.24 m/s²
We are told that this kind of car operates with constant force. This means it operates with constant acceleration (since force and acceleration are directly proportional)
Therefore, when the final velocity of the car is 62 mph (27.72 m/s), time taken is:
a = (v - u) / t
=> t = (v - u) / a
t = (27.72 - 0) / 9.24
t = 3 seconds
It will take the car 5 seconds to go from zero to 62 mph.
