He has 1 1/30 gallons, or 31/30 gallons, you can find this by setting all the fractions to a common denominator and adding them
Answer:
to the right
Explanation:
The balls collide in a completely inelastic collision, in other words they have the same velocity after the collision, this velocity has a magnitude V.
We need to use the conservation of momentum Law, the total momentum is the same before and after the collision.
In the axis X:
(1)
Answer:
Explanation: The field of a magnet is strongest at either pole of the magnet. it's equally strong at the North Pole when put next with the South Pole. The force is weaker within the middle of the magnet and halfway between the pole and also the center.
42.5g
Explanation:
Given parameters:
Mass of N₂= 35g
Unknown:
Mass of NH₃ = ?
Solution:
Equation of the reaction:
N₂ + 3H₂ → 2NH₃
To solve this problem, we work from the known species to the unknown. The known here is the reacting mass of the N₂. From this we can find the number of moles of the N₂.
Number of moles of N₂ = ![\frac{mass}{molar mass}](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7Bmolar%20mass%7D)
molar mass of N₂ = 28g/mol
Number of moles =
= 1.25moles
From the equation of the reaction:
1 mole of N₂ produced 2 moles of NH₃
1.25 moles of N₂ will produce 2 x 1.25 = 2.5moles of NH₃
Mass of NH₃ = Number of moles of NH₃ x molar mass of NH₃
= 2.5 x (14 + 3)
= 42.5g
Learn more:
number of moles brainly.com/question/1841136
#learnwithBrainly
Answer:
a) ![t_r = 0.55 s](https://tex.z-dn.net/?f=t_r%20%3D%200.55%20s)
b) a = 5.59 m/s²
Explanation:
given,
total distance traveled by the car to stop is 56.9 m when speed of vehicle is 80 km/h or 80 × 0.278 = 22.24 m/s
total distance traveled by the car to stop is 25.7 m when speed of vehicle is 50.7 km/h or 50.7 × 0.278 = 14.09 m/s
using stopping distance formula
................(1)
..............(2)
on solving both the equation we get
![a = \dfarc{v_1v_2(v_1-v_2)}{2(s_1v_2-s_2v_1)}](https://tex.z-dn.net/?f=a%20%3D%20%5Cdfarc%7Bv_1v_2%28v_1-v_2%29%7D%7B2%28s_1v_2-s_2v_1%29%7D)
![a = \dfarc{22.4\times 14.09(22.24-14.09)}{2(56.9\times 14.09-25.7\times 22.24)}](https://tex.z-dn.net/?f=a%20%3D%20%5Cdfarc%7B22.4%5Ctimes%2014.09%2822.24-14.09%29%7D%7B2%2856.9%5Ctimes%2014.09-25.7%5Ctimes%2022.24%29%7D)
a = 5.59 m/s²
now reaction time calculation
![t_r =\dfrac{v_1^2d_2-v_2^2d_1}{v_1v_2(v_1-v_2)}](https://tex.z-dn.net/?f=t_r%20%3D%5Cdfrac%7Bv_1%5E2d_2-v_2%5E2d_1%7D%7Bv_1v_2%28v_1-v_2%29%7D)
![t_r =\dfrac{22.24^2\times 25.7-14.09^2\times 56.9}{22.4\times 14.09(22.24-14.09)}](https://tex.z-dn.net/?f=t_r%20%3D%5Cdfrac%7B22.24%5E2%5Ctimes%2025.7-14.09%5E2%5Ctimes%2056.9%7D%7B22.4%5Ctimes%2014.09%2822.24-14.09%29%7D)