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MissTica
3 years ago
12

A boat, the speed of which is 10 m.s-1 relative to the water, sails downstream at an angle of 60 degrees, with the flow of the r

iver current. The current flows at 4m.s-1. What is the resultant velocity of the boat?
Physics
1 answer:
Tems11 [23]3 years ago
4 0

Answer:

resultant velocity of boat will be 11.2249 m/sec          

Explanation:

We have given speed of boat v_b = 10 m /sec

Velocity pf current flow v_c = 4 m /sec

Angle at which boat is moving = 60°

We have to find the resultant velocity

We know that resultant velocity is given by v_r=\sqrt{v_b^2+v_c^2+2v_bv_rcos\Theta}=\sqrt{10^2+4^2+2\times 10\times 4cos60^{\circ}}=11.2249m/sec

So resultant velocity of boat will be 11.2249 m/sec

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vfiekz [6]

The potential difference comes out to be

10 \times 10 {}^{ - 3} m

Given:

σ = 8. 85 × 10-9 c/m2

we know,

E = \frac{σ}{2ε0}

E =  \frac{8.85 \times 10 {}^{ - 9} }{2ε0}

E =  \frac{v}{d}

given the potential difference between two equipotential surface=5v

E=∆v

∆d=∆v/E

=  \frac{5 \times 8.85 \times 10 { }^{ - 12} \times 2 }{8.85 \times 10 {}^{ - 9} }

Δ = 10 \times 10 {}^{ - 3} m

Thus the potential difference is

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Learn more about potential difference from here: brainly.com/question/28165869

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Answer:

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Explanation:

<u><em>Finding the net force:</em></u>

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F_{k} = (micro)_{k}mg

Where (micro)_{k} is the coefficient of friction and m = 13.6 kg

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<u><em>Now, Finding the net force:</em></u>

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F_{net} = 28.7 \ N

<u><em>Finding Acceleration:</em></u>

a = \frac{F_{net}}{m}

a = \frac{28.7}{13.6}

a = 2.1 \ m/s^2

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