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trapecia [35]
3 years ago
7

Help me plzzzzzz! Can someone help me with number 4 Idon’t get it

Physics
2 answers:
ryzh [129]3 years ago
6 0
Pollution of the spheres has impacted is the answer I think
andrew11 [14]3 years ago
5 0
I can only think of one at the moment but I would say that pollution and greenhouse gases have impacted out atmosphere. You could mention cars and factories. You could also say that oil spills and trash have impacted the hydrosphere.
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It takes 20s for 3x10^6 electrons to flow through a wire ,what is the current?
Elina [12.6K]

Answer:

Explanation:

The variables we know and are given are:

time, t = 20s

Charge, Q = 3x1-^-6 electrons, which is just 3x10^-6C (C stands for Coulombs, which is the unit for Charge)

We need to find the current, I, and since we know Q and t we can substitute these values into the given equation:

I=Q/t (which if you look at what the RHS is saying, its Charge over time, or more literally means the amount of charge passing a point over a period of time)

If we substitute these values, we will get I as:

I = Q / t

I = 3x10^-6 / 20

I = 1.5x10^-7 A

Hope this helps!

6 0
3 years ago
Which characteristic would you expect from a sample with a pH of 9
Verizon [17]
I would expect it to be slightly basic.
7 0
3 years ago
Which statement about the image Formed by a plane mirror is correct?
lbvjy [14]

Answer:

The image is virtual

number-4

8 0
3 years ago
During which of the following chemical changes does a precipitate form?
babymother [125]

Answer is B.........

5 0
3 years ago
Read 2 more answers
Radar uses radio waves of a wavelength of 2.9 m . The time interval for one radiation pulse is 100 times larger than the time of
Mandarinka [93]

Answer:

145 m

Explanation:

Given:

Wavelength (λ) = 2.9 m  

we know,

c = f × λ  

where,

c = speed of light ; 3.0 x 10⁸ m/s

f = frequency  

thus,

f=\frac{c}{\lambda}

substituting the values in the equation we get,

f=\frac{3.0\times 10^8 m/s}{2.9m}

f = 1.03 x 10⁸Hz  

Now,

The time period (T) = \frac{1}{f}

or

T =  \frac{1}{1.03\times 10^8}  = 9.6 x 10⁻⁹ seconds  

thus,

the time interval of one pulse = 100T = 9.6 x 10⁻⁷ s  

Time between pulses = (100T×10) = 9.6 x 10⁻⁶ s  

Now,

For radar to detect the object the pulse must hit the object and come back to the detector.

Hence, the shortest distance will be half the distance travelled by the pulse back and forth.

Distance = speed × time = 3 x 10^8 m/s × 9.6 x 10⁻⁷ s) = 290 m {Back and forth}  

Thus, the minimum distance to target = \frac{290}{2} = 145 m

6 0
2 years ago
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