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3 years ago

Help me plzzzzzz! Can someone help me with number 4 Idon’t get it

Physics

2 answers:

ryzh [129]3 years ago

6 0

Pollution of the spheres has impacted is the answer I think

andrew11 [14]3 years ago

5 0

I can only think of one at the moment but I would say that pollution and greenhouse gases have impacted out atmosphere. You could mention cars and factories. You could also say that oil spills and trash have impacted the hydrosphere.

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Item 19 Question 1 A Ferris wheel has a radius of 75 feet. You board a car at the bottom of the Ferris wheel, which is 10 feet a

sergey [27]

Answer:

$y = 104.4 ft$

Explanation:

As we know that we board in the car of ferris wheel at the bottom position

So we will have

final height of the car at angular displacement given as

$y = y_o + R + R sin(270 - 255)$

$y = y_o + R + R sin 15$

here we know that

$y_o = 10 ft$

$R = 75 ft$

so we have

$y = 10 + 75 + 75 sin15$

$y = 104.4 ft$

4 0

2 years ago

Why won't a very bright beam of red light impart more energy to an ejected electron than a feeble beam of violet light?

bearhunter [10]

This is related to the energy carried by photons of light the energy of each photon is proportional to the frequency of the light since red light has a lower frequency then violet light and photons of red light carry less energy than the photons of violet light as a result the red protons eject electrons that have less energy than the ejected electrons by Violet photons

3 0

2 years ago

Electricity does not commonly occur in nature except in the form of ( hydrocarbons, photosyntheis, lightning, thunder)

horrorfan [7]

Hydrocarbons are compounds of hydrogen and carbon.
Photosynthesis is a process of nutrition in plants.
Thunder is a sound.
Lightning and electric eels are electrical phenomena in nature.

7 0

3 years ago

Read 2 more answers

Prior to the Panama Canal, __________ was a major route between the Atlantic and Pacific oceans.

Bingel [31]

The Rio Grande was the major route prior to the Panama Canal.

3 0

3 years ago

Read 2 more answers

Simple question please help! A ball is thrown 19.0 m/s at an angle of 40.0º with the horizontal. Assume the ball is thrown at gr

d1i1m1o1n [39]

a. 1.51 s

In this part of the problem, we are only interested in the horizontal motion of the ball. Along the horizontal direction, the motion of the ball is a uniform motion with constant velocity, which is equal to the horizontal component of the initial velocity:

$v_x = v_0 cos \theta = (19.0 m/s)(cos 40^{\circ})=14.6 m/s$

So, the ball travels horizontally at a speed of 14.6 m/s; in order to cover the distance of d = 22.0 m that separates it from the wall, the time need is

$t=\frac{d}{v_x}=\frac{22.0 m}{14.6 m/s}=1.51 s$

b. 7.25 m

We now know that the ball takes 1.51 s to hit the wall, 22.0 away. Now we have to analyze the vertical motion of the ball, which is an accelerated motion with constant acceleration g =9.8 m/s^2 towards the ground (acceleration due to gravity).

The initial vertical velocity is

$v_{y0}=v_0 sin \theta=(19.0 m/s)(sin 40^{\circ})=12.2 m/s$

The vertical position of the ball at time t is given by the equation

$y(t)=v_{0y} t -\frac{1}{2}gt^2$

We know that the ball hits the wall at t=1.51 s, so if we substitute this value into the previous formula, we find at what height y the ball hits the wall:

$y(1.51 s)=(12.2 m/s)(1.51 s)-\frac{1}{2}(9.8 m/s^2)(1.51 s)^2=7.25 m$

7 0

3 years ago