Botany is the study of plants. Study of classifying organisms is taxonomy.
Reduction Reaction:
Ag⁺ + 1e⁻ → Ag ------ (1)
Oxidation Reaction:
NO₂⁻ → NO₃⁻ + 2e⁻
Balance Oxygen atoms, by adding H₂O to side having less number of O atoms, and H⁺ to side having greater number of O atoms.
NO₂⁻ + H₂O → NO₃⁻ + H⁺ + 2e⁻
Balance the H⁺'s,
NO₂⁻ + H₂O → NO₃⁻ + 2 H⁺ + 2e⁻ ------ (2)
Multiply eq. 1 by 2 to balance the number of electrons in overall reaction.
2 Ag⁺ + 2e⁻ → 2 Ag ----- (3)
Compare eq. 2 and 3,
NO₂⁻ + H₂O → NO₃⁻ + 2 H⁺ + 2e⁻
2 Ag⁺ + 2e⁻ → 2 Ag
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NO₂⁻ + H₂O + 2 Ag⁺ → NO₃⁻ + 2 Ag + 2 H⁺
<u>Answer:</u> The molarity of solution is 1.08 M
<u>Explanation:</u>
We are given:
(m/m) of phenol = 1.40 %
This means that 1.40 g of phenol is present in 100 g of solution.
To calculate volume of solution, we use the equation:
Density of solution = 0.9956 g/mL
Mass of solution = 100 g
Putting values in above equation, we get:
To calculate the molarity of solution, we use the equation:
We are given:
Mass of solute (phenol) = 1.40 g
Molar mass of phenol = 94.11 g/mol
Volume of solution = 100.442 mL
Putting values in above equation, we get:
Hence, the molarity of solution is 0.15 M
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