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Phantasy [73]
3 years ago
11

Which expression correctly describes energy using Sl units?

Engineering
1 answer:
Tasya [4]3 years ago
7 0

Answer:

A. 1 J = 1 kg.m²/s²

Explanation:

Energy is defined as the ability to do work. The most basic equation or formula to find the magnitude of energy is given in terms of work. That formula is written as follows:

Energy = Work

Energy = Force * Displacement

Replacing these variables, with their S.I units:

Joule = Newton*m

where,

Force (Newton) = mass (kg) * acceleration (m/s²)

Newton = kg.m/s²

Therefore,

Joule = (kg.m/s²)(m)

<u>A. 1 J = 1 kg.m²/s²</u>

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Explain why the following scenario fails to meet the criteria for proper reverse engineering.
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Answer:

he must document or remember the order he took it apart so he put it back together

Explanation:

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Responding to the campaign of 4 classes, 7A, 7B, 7C, 7D contributed the amount of support proportional to the numbers 8,6;7;5 kn
Zolol [24]

Writing life on my fantasy planet

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Which lens is wide-angle?
PIT_PIT [208]

A wide-angle lens has a focal length of 35mm or shorter, which gives you a wide field of view. The wider your field of view, the more of the scene you'll be able to see in the frame. These lenses are ideal for many scenarios, and most photographers have at least one trusty wide-angle lens in their kit.

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5 0
2 years ago
A tensile test was operated to test some important mechanical properties. The specimen has a gage length = 1.8 in and diameter =
oee [108]

Answer:

a) 60000 psi

b) 1.11*10^6 psi

c) 112000 psi

d) 30.5%

e) 30%

Explanation:

The yield strength is the load applied when yielding behind divided by the section.

yield strength = Fyield / A

A = π/4 * D^2

A = 0.5 in^2

ys = Fy * A

y2 = 30000 * 0.5 = 60000 psi

The modulus of elasticity (E) is a material property that is related to the object property of stiffness (k).

k = E * L0 / A

And the stiffness is related to change of length:

Δx = F / k

Then:

Δx = F * A / (E * L0)

E = F * A / (Δx * L0)

When yielding began (approximately the end of the proportional peroid) the force was of 30000 lb and the change of length was

Δx = L - L0 = 1.8075 - 1.8 = 0.0075

Then:

E = 30000 * 0.5 / (0.0075 * 1.8) = 1.11*10^6 psi

Tensile strength is the strees at which the material breaks.

The maximum load was 56050 lb, so:

ts = 56050 / 0.5 = 112000 psi

The percent elongation is calculated as:

e = 100 * (L / L0)

e = 100 * (2.35 / 1.8 - 1) = 30.5 %

If it necked with and area of 0.35 in^2 the precent reduction in area was:

100 * (1 - A / A0)

100 * (1 - 0.35 / 0.5) = 30%

5 0
3 years ago
A(n) 78-hp compressor in a facility that operates at full load for 2500 h a year is powered by an electric motor that has an eff
Jet001 [13]

Answer: $17,206.13

Explanation:

Hi, to answer this question we have to apply the next formula:  

Annual electricity cost = (P x 0.746 x Ckwh x h) /η  

P = compressor power = 78 hp  

0.746 kw/hp= constant (conversion to kw)

Ckwh = Cost per kilowatt hour = $0.11/kWh  

h = operating hours per year = 2500 h  

η = efficiency = 93% = 0.93 (decimal form)  

Replacing with the values given :  

C = ( 78 hp x 0.746 kw/hp x 0.11 $/kwh x 2500 h ) / 0.93 = $17,206.13  

5 0
3 years ago
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