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3 years ago

What will happen in a wire drawing operation when the cross-sectional area has a reduction of 60% in a single pass?

Engineering

1 answer:

Fofino [41]3 years ago

4 0

Answer:

DRAWING LOAD IS $3.67 A_{O}\sigma$

Explanation:

wire drawing is a method of obtaining wire of bigger large diameter from iron rod . it is cold process which need die to obtain wire

drawing load for wire drawing is given as P = $A_{F}*\sigma*ln(\frac{A_{O}}{A_{F}})$

Where A f is initial area, Ao is original area, σ is yield stress

as given in question sectional area reduce 60%, therefore

$A_{f} = A_{O}- 0.6A_{O}$

= $0.4 A_{O}$

Due to change in area ,drawing load p is

p = $0.4A_{O}*\sigma*ln(\frac{A_{O}}{0.4A_{O}})$

p = $3.67 A_{O}\sigma$

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2 years ago

A wastewater treatment plant has two primary clarifiers, each 20m in diameter with a 2-m side-water depth. the effluent weirs ar

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Answer:

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Explanation:

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2 years ago

With reference to the NSPE Code of Ethics, which one of the following statements is true regarding the ethical obligations of th

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3 years ago

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Answer:

Following are the proving to this question:

Explanation:

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$\to \frac{p_o}{y} +\frac{V^{2}_{o}}{2g}+Z_0 = \frac{p_1}{y} +\frac{V^{2}_{1}}{2g}+Z_1+ f \frac{l}{D}\frac{V^{2}}{2g}$

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