What will happen in a wire drawing operation when the cross-sectional area has a reduction of 60% in a single pass?
1 answer:
Answer:
DRAWING LOAD IS
Explanation:
wire drawing is a method of obtaining wire of bigger large diameter from iron rod . it is cold process which need die to obtain wire
drawing load for wire drawing is given as P =
Where A f is initial area, Ao is original area, σ is yield stress
as given in question sectional area reduce 60%, therefore
=
Due to change in area ,drawing load p is
p =
p =
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Answer:
Explanation:
Given data:
initial construction co = 0.286 wt %
concentration at surface position cs = 0 wt %
carbon concentration cx = 0.215 wt%
time = 7 hr
for 0.225% carbon concentration following formula is used
where, erf stand for error function
from the table erf(Z) value = 0.751 lie between (z) = 0.80 and z = 0.85 so by inteerpolation we have z = 0.815
from given table
x = 0.002395 mm
Answer:
E=52000Hp.h
E=38724920Wh
E=1.028x10^11 ftlb
Explanation:
To solve this problem you must multiply the engine power by the time factor expressed in h / year, to find this value you must perform the conventional unit conversion procedure.
Finally, when you have the result Hp h / year you convert it to Ftlb and Wh
E=52000Hp.h
E=38724920Wh
E=1.028x10^11 ftlb