Question

What will happen in a wire drawing operation when the cross-sectional area has a reduction of 60% in a single pass?

Answer 1

Answer:

DRAWING LOAD IS  $3.67 A_{O}\sigma$

Explanation:

wire drawing is a method of obtaining wire of bigger large diameter from iron rod . it is cold process which need die to obtain wire

drawing load for wire drawing is given as P = $A_{F}*\sigma*ln(\frac{A_{O}}{A_{F}})$

Where A f is initial area, Ao is original area, σ is yield stress

as given in question sectional area reduce 60%, therefore

$A_{f} = A_{O}- 0.6A_{O}$

    = $0.4 A_{O}$

Due to change in area ,drawing load p is

p = $0.4A_{O}*\sigma*ln(\frac{A_{O}}{0.4A_{O}})$

p = $3.67 A_{O}\sigma$