<span>The average weather of a particular place is "Climate"
In short, Your Answer would be Option B
Hope this helps!</span>
When the oscillator is at maximum extension, we know all of its energy is in Potential Energy, so if the total oscillation energy is 4.1 J, we know that at maximum displacement of 0.2 m, that
<span>energy = 1/2 kA^2 where A= 0.2 m </span>
<span>k= 2E / A^2 = 2*4.1 J /0.2^2=200 N/m </span>
<span>the frequency of oscillation is (1/2pi) sqrt[k/m] </span>
<span>knowing k and m, we can substitute values and find frequency</span>
B is the correct q2ureire awej\
Answer:
a. It became deeper by a factor of 3.
Explanation:
What we have is water flowing down a river with constant width. The water slows from speed v to v3 over a shirt distance
Using the equation of continuity
A1V1 = A2V2 ----1
A1 is the area of rectangle
V1 is the velocity of water
Area of rectangle = length x width
We rewrite equation 1 as
λ1w1v1 = λ2w2v2
We have w1 = w2
λ1v1 = λ2v2
λ1*v1 = λ2*v/3
λ1 = λ2/3
So it becomes deeper by a factor of 3