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igomit [66]
3 years ago
8

Which best describes how an ionic bond forms? A.Two molecules share an electron. B.One atom pulls an electron from another atom.

C.Two atoms share valence electrons. D.Two atoms both lose an electron.
Chemistry
2 answers:
Tema [17]3 years ago
3 0
Your answer Should be B

babunello [35]3 years ago
3 0

Answer:

The correct answer is B.One atom pulls an electron from another atom.

Explanation:

Chemical bonds are made so that atoms can have their entire outer layer, and thus have a stable electronic configuration.

An ionic bond is produced between metallic and non-metallic atoms, where electrons are completely transferred from one atom to another. During this process, one atom loses electrons and another one gains them, forming ions. Usually, the metal gives up its electrons forming a cation to the nonmetal element, which forms an anion.

So, <u><em>the correct answer is B.One atom pulls an electron from another atom.</em></u>

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0.5

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Lo llamas hidrostática

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How is 1 hectoliter different from 1 kiloliter?
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The activation energy for proline isomerization of a peptide depends on the identity of the preceding residue and obeys Arrheniu
MAVERICK [17]

Answer:

Activation energy of phenylalanine-proline peptide is 66 kJ/mol.

Explanation:

According to Arrhenius equation-     k=Ae^{\frac{-E_{a}}{RT}}    , where k is rate constant, A is pre-exponential factor, E_{a} is activation energy, R is gas constant and T is temperature in kelvin scale.

As A is identical for both peptide therefore-

                                   \frac{k_{ala-pro}}{k_{phe-pro}}=e^\frac{[E_{a}^{phe-pro}-E_{a}^{ala-pro}]}{RT}

Here \frac{k_{ala-pro}}{k_{phe-pro}}=\frac{0.05}{0.005} , T = 298 K , R = 8.314 J/(mol.K) and E_{a}^{ala-pro}=60kJ/mol

So, \frac{0.05}{0.005}=e^{\frac{[E_{a}^{phe-pro}-(60000J/mol)]}{8.314J.mol^{-1}.K^{-1}\times 298K}}

   \Rightarrow E_{a}^{phe-pro}=65705J/mol=66kJ/mol (rounded off to two significant digit)

So, activation energy of phenylalanine-proline peptide is 66 kJ/mol

7 0
3 years ago
What volume in L of a 0.724 M Nal solution contains 0.405 mol of Nal?
Setler [38]

Answer:

0.559 L

Explanation:

Step 1: Given data

  • Moles of sodium iodide (n): 0.405 mol
  • Molar concentration of sodium iodide (M): 0.724 M (0.724 mol/L)

Step 2: Calculate the volume of solution (V)

The molarity is equal to the moles of solute divided by the liters of solution.

M = n/V

V = n/M

V = 0.405 mol/(0.724 mol/L) = 0.559 L

4 0
3 years ago
Read 2 more answers
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