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Paladinen [302]
2 years ago
9

Calculate the formula mass of Cuso4​

Chemistry
1 answer:
Mandarinka [93]2 years ago
3 0
Answer: 159.61 g/mol

Copper has a molar mass of 63.546 g/mol

Sulfur has a molar mass of 32.065 g/mol

Oxygen has a molar mass of 16 g/mol, multiply by 4 and it is 16 x 4 = 64 g/mol

63.546 + 32.065 + 64 = 159.61 g/mol
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Calculate the initial rate for the formation of C at 25 ∘C, if [A]=0.50M and [B]=0.075M.Express your answer to two significant f
N76 [4]

The question is incomplete, here is the complete question:

Calculate the initial rate for the formation of C at 25°C, if [A]=0.50 M and [B]=0.075 M. Express your answer to two significant figures and include the appropriate units.Consider the reaction

A + 2B ⇔ C

whose rate at 25°C was measured using three different sets of initial concentrations as listed in the following table:

The table is attached below as an image.

<u>Answer:</u> The initial rate for the formation of C at 25°C is 2.25\times 10^{-2}Ms^{-1}

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

A+2B\rightleftharpoons C

Rate law expression for the reaction:

\text{Rate}=k[A]^a[B]^b

where,

a = order with respect to A

b = order with respect to B

  • Expression for rate law for first trial:

5.4\times 10^{-3}=k(0.30)^a(0.050)^b ....(1)

  • Expression for rate law for second trial:

1.1\times 10^{-2}=k(0.30)^a(0.100)^b ....(2)

  • Expression for rate law for third trial:

2.2\times 10^{-2}=k(0.50)^a(0.050)^b ....(3)

Dividing 2 by 1, we get:

\frac{1.1\times 10^{-2}}{5.4\times 10^{-3}}=\frac{(0.30)^a(1.00)^b}{(0.30)^a(0.050)^b}\\\\2=2^b\\b=1

Dividing 3 by 1, we get:

\frac{2.2\times 10^{-2}}{5.4\times 10^{-3}}=\frac{(0.50)^a(0.050)^b}{(0.30)^a(0.050)^b}\\\\4.07=2^a\\a=2

Thus, the rate law becomes:

\text{Rate}=k[A]^2[B]^1       ......(4)

Now, calculating the value of 'k' by using any expression.

Putting values in equation 1, we get:

5.4\times 10^{-3}=k[0.30]^2[0.050]^1\\\\k=1.2M^{-2}s^{-1}

Calculating the initial rate of formation of C by using equation 4, we get:

k=1.2M^{-2}s^{-1}

[A] = 0.50 M

[B] = 0.075 M

Putting values in equation 4, we get:

\text{Rate}=1.2\times (0.50)^2\times (0.075)^1\\\\\text{Rate}=2.25\times 10^{-2}Ms^{-1}

Hence, the initial rate for the formation of C at 25°C is 2.25\times 10^{-2}Ms^{-1}

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3 years ago
Identify the correct statement regarding the strength of chemical bonds.
allsm [11]

Answer:

<h2>B)</h2><h2><u><em>brainlist plz</em></u></h2>

Explanation:

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3 years ago
In a titration experiment, how many moles of naoh will be required to completely neutralize 1 mole of nitric acid?
katrin [286]

Answer:

One mole

Explanation:

The balanced chemical equation is

<u>1</u>NaOH + <u>1</u>HNO₃ ⟶ NaNO₃ + H₂O

<u>1</u> mol       <u>1</u> mol

The coefficients in front of the formulas tell you the amount of something that reacts with an equivalent amount of something else.

In this reaction, 1 mol NaOH reacts with 1 mol HNO₃.

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Which of the following questions is outside the scope of science?
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A. How religion and philosophy different
All the other choices (b-d) can be explained by science while a can be explain by history I think
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3. What is the easiest way to create electron configurations?
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Answer:

To calculate an electron configuration, divide the periodic table into sections to represent the atomic orbitals, the regions where electrons are contained. Groups one and two are the s-block, three through 12 represent the d-block, 13 to 18 are the p-block and the two rows at the bottom are the f-block.Explanation:

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3 years ago
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