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Andreyy89
3 years ago
10

A distance of 2.5 meters separates two similar balls of mass 0.70 kg each. Calculate the force of gravity between the two balls.

Physics
1 answer:
pav-90 [236]3 years ago
7 0

Answer:

2

Explanation:

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The correct answer to this question is D
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Como surgiu a capoeira?
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A horse of mass 242 kg pulls a cart of mass 224 kg. The acceleration of gravity is 9.8 m/s 2 . What is the largest acceleration
Rufina [12.5K]

To solve this problem it is necessary to apply the concepts related to Newton's second Law and the force of friction. According to Newton, the Force is defined as

F = ma

Where,

m= Mass

a = Acceleration

At the same time the frictional force can be defined as,

F_f = \mu N

Where,

\mu = Frictional coefficient

N = Normal force (mass*gravity)

Our values are given as,

m_h = 242 kg\\m_c = 224 kg\\\mu = 0.894\\

By condition of Balance the friction force must be equal to the total net force, that is to say

F_{net} = F_f

m_{total}a = \mu m_hg

(m_h+m_c)a = \mu*m_h*g

Re-arrange to find acceleration,

a= \frac{\mu*m_h*g}{(m_h+m_c)}

a = \frac{0.894*242*9.8}{(242+224)}

a = 4.54 m/s^2

Therefore the acceleration the horse can give is 4.54m/s^2

3 0
3 years ago
You need to design a 60.0-Hz ac generator that has a maximum emf of 5200 V. The generator is to contain a 130-turn coil that has
dimaraw [331]

Answer:

B =  0.129 T

Explanation:

Given,

frequency, f = 60 Hz

maximum  emf = 5200 V

Number of turns, N = 130

Area per turn = 0.82 m²

We know,

ω = 2 π f

ω = 2 π x 60 = 376.99 rad/s

now, Magnetic field calculation

B =\dfrac{\epsilon_{max}}{NA\omega}

B =\dfrac{5200}{130\times 0.82\times 376.99}

B =  0.129 T

Hence, the magnetic field is equal to B =  0.129 T

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3 years ago
A situation known as ( blank)
Lisa [10]

Answer:

Apparent weightlessness

Explanation:

6 0
3 years ago
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