A distance of 2.5 meters separates two similar balls of mass 0.70 kg each. Calculate the force of gravity between the two balls.
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Answer:
Approximate height of the building is 23213 meters.
Explanation:
Let the height of the building be represented by h.
0.02 radians = 0.02 ×
= 0.02 x (180/)
0.02 radians = 1.146°
10.5 km = 10500 m
Applying the trigonometric function, we have;
Tan θ =
So that,
Tan 1.146° =
⇒ h = Tan 1.146° x 10500
= 2.21074 x 10500
= 23212.77
h = 23213 m
The approximate height of the building is 23213 m.