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Andreyy89
3 years ago
10

A distance of 2.5 meters separates two similar balls of mass 0.70 kg each. Calculate the force of gravity between the two balls.

Physics
1 answer:
pav-90 [236]3 years ago
7 0

Answer:

2

Explanation:

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Ifa truck starts from rest and it has acceleration of 4 m/s for 5 second
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Answer:

Distance 50m

final velocity 20ms^-1

s = ut +  \frac{1}{2} a {t}^{2}  \\  = 0 \times t +  \frac{1}{2} \times 4 \times  {5}^{2}   = 50m

v = u + at \\ v = 0 + 4 \times 5 \\ v = 20ms^{ - 1}

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A 1700kg rhino charges at a speed of 50.0km/h. what average force is needed to bring the rhino to a stop in 0.50s?
uranmaximum [27]
From 50km/h to 0km/h in 0.5s we need next acceleration:
First we convert km/h in m/s:
50km/h = 50*1000/3600=13.8888 m/s
a = v/t = 13.88888/0.5 = 27.77777 m/s^2

Now we use Newton's law:

F=m*a

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4 years ago
Two rocks, A and B, are thrown horizontally from the top of a cliff. Rock A has an initial speed of 10 meters per second and roc
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2 years ago
A car is moving with an initial relocity of
MA_775_DIABLO [31]

Answer:

The final acceleration of the car, v = 70 m/s

Explanation:

Given,

The initial velocity of the car, u = 20 m/s

The acceleration of the car, a = 10 m/s²

The time period of travel, t = 5 s

Using the I equations of motion

                     v = u + at

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3 years ago
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