Answer:
Zero
Explanation:
Average velocity is given by:
where
d is the displacement of the trip
t is the time it takes for the trip to complete
In this problem, the net displacement of the swimmer is zero. In fact:
- First, he swims 30.0 m in the north direction
- Then, he travels back (-30.0 m) in the south direction, to the starting position
Since the final position is equal to the starting position, the displacement is zero:
d = 0
And therefore, the average velocity is also zero.
The image of the black body curve is missing, so i have attached it.
Answer:
T ≈ 3372 K
Explanation:
From the attached curve of the black star, if we trace the peak value of the wavelength from the graph, we will see that it is approximately 859.5 nm.
Thus; λ_peak = 859.5 × 10^(-9) m
From wiens law, we know that;
T•λ_peak = 2.898 × 10^(-3) m.K
Where T is surface temperature.
Plugging in the relevant values, we can find the temperature T
Thus;
T = (2.898 × 10^(-3))/(859.5 × 10^(-9))
T ≈ 3372 K
Answer:
Force constant, k = 653.3 N/m
Explanation:
It is given that,
Weight of the bag of oranges on a scale, W = 22.3 N
Let m is the mass of the bag of oranges,
m = 2.27 kg
Frequency of the oscillation of the scale, f = 2.7 Hz
We need to find the force constant (spring constant) of the spring of the scale. We know that the formula of the frequency of oscillation of the spring is given by :
k = 653.3 N/m
So, the force constant of the spring of the scale is 653.3 N/m. Hence, this is the required solution.