A distance of 2.5 meters separates two similar balls of mass 0.70 kg each. Calculate the force of gravity between the two balls.
1 answer:
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To solve this problem it is necessary to apply the concepts related to Newton's second Law and the force of friction. According to Newton, the Force is defined as
F = ma
Where,
m= Mass
a = Acceleration
At the same time the frictional force can be defined as,
Where,
Frictional coefficient
N = Normal force (mass*gravity)
Our values are given as,
By condition of Balance the friction force must be equal to the total net force, that is to say
Re-arrange to find acceleration,
Therefore the acceleration the horse can give is
Answer:
B = 0.129 T
Explanation:
Given,
frequency, f = 60 Hz
maximum emf = 5200 V
Number of turns, N = 130
Area per turn = 0.82 m²
We know,
ω = 2 π f
ω = 2 π x 60 = 376.99 rad/s
now, Magnetic field calculation
B = 0.129 T
Hence, the magnetic field is equal to B = 0.129 T