Determine the oxidation states of the elements in the compounds listed. None of the oxygen-containing compounds are peroxides or
superoxide.
(a)H3PO4
(b)Al(OH)3
(c)SeO2
(d)KNO2
(e)In2S3
(f)P4O6
(a)H3PO4
(b)Al(OH)3
(c)SeO2
(d)KNO2
(e)In2S3
(f)P4O6
1 answer:
Answer:
Explanation:
You need to remember that the oxidation number of H is +1, except when it is in a metal hydrites like NaH, where its oxidation number is -1. Then, the oxidation number of O is -2, but in peroxides is -1. So with these rules you just have to multiply the ox. number with the name of atoms and all the elements in the reaction must sum 0.
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<u>Answer:</u>
<em>A. 10.25</em>
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<u>Explanation:</u>
Pkb =4.77
So pka = 14 - pka = 9.23
Initial 0.50M 0 0
Change -x +x +x
Equilibrium 0.50M-x +x +x
(-x is neglected) so we get
pOH = 14 - pH
= 14 - 4.76
pOH = 9.24 is the answer
Option A - 10.25 is the answer which is close to 9.24
Answer:
Explanation:
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In this case, considering that the decomposition reaction of SO2Cl2 is first-order, we can write the rate law shown below:
We also consider that the integrated rate law has been already reported as:
Thus, by plugging in the initial concentration, rate constant and elapsed time we obtain:
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