Answer:
Put their markers together, now they have each color
Explanation:
<span>Size of the sample there you go hope it helps :>
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Answer:
2×10² cg
Explanation:
We'll begin by converting each of the above to the same unit of measurement.
In this case, we shall convert each of the above to kg. This can be obtained as follow:
Conversion of cg to kg
1 cg = 1×10¯⁵ Kg
Therefore,
2×10² cg = 2×10² × 1×10¯⁵
2×10² cg = 0.002 kg
Conversion of dg to Kg
1 dg = 1×10¯⁴ kg
Therefore,
10 dg = 10 × 1×10¯⁴
10 dg = 0.001 kg
Conversion of mg to kg.
1 mg = 1×10¯⁶ Kg
Therefore,
2×10² mg = 2×10² × 1×10¯⁶
2×10² mg = 0.0002 kg
Conversion of ng to kg
1 ng = 1×10¯¹² kg
Therefore,
1×10⁵ ng = 1×10⁵ × 1×10¯¹²
1×10⁵ ng = 0.0000001 Kg
Summary
1. 2×10² cg = 0.002 kg
2. 10 dg = 0.001 kg
3. 2×10² mg = 0.0002 kg
4. 0.001 kg
5. 1×10⁵ ng = 0.0000001 Kg
From the above calculation, 2×10² cg is the highest mass.
True. Modern theory of Atom is still using the proposed ideas of Dalton, Thomson and Rutherford.
Explanation:
- Dalton created his atom theory - He said that all matter is made up of atoms and atoms can’t be created nor destroyed or divided into tiny particles. In the same element, all atoms will be identical in size and mass but atoms in the one element will be different in size and mass from the atoms in the other elements. Atoms of different elements combined and forming compounds.
- Thomson found that inferred atoms and negative electrons also contains the negative particles. He also concluded that there was a mass of positively charged material. He explained this with the Raisins Bun model.
- Using Gold Foil Experiment Rutherford found the positively charged nucleus in the centre of every atom. When he was doing this experiment, the positive particles which he passed through the foil got reflected at the centre. This led Rutherford to conclude about the positively charged nucleus at the centre. And he also found about revolving electrons around the nucleus because, in his experiment, some of the positive particles got attracted near the centre.
