Answer:
Therefore,
a)
b)
c) distance from the sphere's surface = 1.8 cm
Explanation:
Given:
Radius, r = 11 cm = 0.11 m
Charge,
To Find:
a) electric field at the sphere's surface = ?
b) If V = 0 at infinity, what is the electric potential at the sphere's surface = ?
c) At what distance from the sphere's surface has the electric potential decreased by 320 V = ?
Solution:
Electric field at the sphere's surface is given as,
Where,
E = Electric Field,
Q = Charge
r = Radius
Substituting the values we get
Now, Electric Potential at point surface is given as,
Substituting the values we get
For distance from the sphere's surface has the electric potential decreased by 320 V,
So V becomes,
V = 2290 - 320 = 1970 Volt, then r =?
Substituting the values we get
Therefore the distance from the sphere's surface,
Therefore,
a)
b)
c) distance from the sphere's surface = 1.8 cm