The term pKa refers to the negative logarithm of the acid dissociation constant (Ka). The pH is the negative logarithm of the hydrogen ion concentration.

Hence;

Ka = Antilog (-6) = $1 * 10^-6$

[H^+] = Antilog (-7.5) = $3 * 10^-8 M$

We now have to use the formula;

α = $\sqrt{} \frac{Ka}{[H^+] }$

α = $\sqrt{} \frac{ 1 *10^-6}{3 *10^-8 }$

α = 5.77 %

Hence, the percent of histidine side chains would be deprotonated at pH 7.5 is 5.77 %.

Learn more about percent dissociation: brainly.com/question/12273293

3 0

3 years ago

2.5 million atoms of a particular element have a mass of 8.33 x 10-16 grams. what is this element

jeyben [28]

Find the mass of one atom by:

8.33 x 10^{-16} / 2.5 x 10^{6} = 3.32 x 10^{-22} g

Convert it into amu.
1 g = 6.022 x 10^{23} amu
so, 3.32 x 10^{-22} x 6.022 x 10^{23} = 200.6 amu

Now look at the periodic table and search for 200.6 amu element.
The element is Mercury (Hg)

5 0

3 years ago

What makes metalloids a group of their own?

mestny [16]

Answer:

The metalloids are in a group of elements in the periodic table we know for the kinds of atom types.

Explanation:

Hope this helps u.. :D

8 0

3 years ago

What is the molar mass of KOH?

Julli [10]

<h3>Answer:</h3>

56.11 g/mol

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Compound] KOH

<u>Step 2: Identify</u>

[PT] Molar Mass of K - 39.10 g/mol

[PT] Molar Mass of O - 16.00 g/mol

[PT] Molar Mass of H - 1.01 g/mol

39.10 + 16.00 + 1.01 = 56.11 g/mol

5 0

3 years ago