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Brums [2.3K]
3 years ago
12

What is the main difference between a maglev train and a normal train?

Physics
1 answer:
professor190 [17]3 years ago
5 0
Regular trains follow train tracks and travel on rails; Maglev trains are Magnetically Levitated using powerful electromagnets, so that they actually hover slightly above the ground. This massively reduces friction and allows them to travel much faster (kind of like how a puck can go really far with only a little push on an air hockey table).
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A car travels at a constant speed up a ramp making an angle of 28 degrees with the horizontal component of velocity is 40 kmh^-1
Hoochie [10]

Answer:

Vx = 35.31 [km/h]

Vy = 18.77 [km/h]

Explanation:

In order to solve this problem, we must decompose the velocity component by means of the angle of 28° using the cosine function of the angle.

v_{x} = 40*cos(28)\\V_{x} = 35.31 [km/h]

In order to find the vertical component, we must use the sine function of the angle.

V_{y}=40*sin(28)\\V_{y} = 18.77 [km/h]

7 0
3 years ago
In nuclear reaction 5 kg of reactants give 2kg of products
dlinn [17]
Choice A is correct.======Kinetic energy equation:   KE = (1/2)(m)(v²)This tells us that KE is directly proportional to mass and the square of velocity. In other words, the more mass and more velocity an object has, the more kinetic energy.If an object is sitting at the top of a ramp, there is no velocity and therefore no kinetic energy.    Choices B and D are wrong.A golf ball has more mass than a ping-pong ball, so a ping-pong ball would have less kinetic energy than a golf ball rolling off the end of a ramp.    Choice C is wrong.Choice A is correct.


6 0
2 years ago
Anything that has mass and occupies space is defined as.
forsale [732]

Answer:

matter is the correct answer.

8 0
2 years ago
A charged particle is moving in a uniform magnetic field at a speed of 8.2Ã10^3 m/s in a direction 87° from the direction of th
77julia77 [94]

Answer:

Magnetic field, B = 0.042 T

Explanation:

It is given that,

Speed of charged particle, v=8.2\times 10^3\ m/s

Angle between velocity and the magnetic field, \theta=87

Charge, q=5.7\ \mu C=5.7\times 10^{-6}\ C

Magnetic force, F = 0.002 N

The magnetic force is given by :

F=qvB\ sin\theta

B is the magnetic field  

B=\dfrac{F}{qv\ sin\theta}

B=\dfrac{0.002}{5.7\times 10^{-6}\times 8.2\times 10^3\times sin(87)}

B = 0.042 T

So, the strength of the magnetic field is 0.042 Tesla. Hence, this is the required solution.

5 0
3 years ago
Please help
iVinArrow [24]
Answer is 4,400,000 kg • m/s
4 0
2 years ago
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