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Hoochie [10]
4 years ago
10

It may seem strange that the selected velocity does not depend on either the mass or the charge of the particle. (For example, w

ould the velocity of a neutral particle be selected by passage through this device?) The explanation of this is that the mass and the charge control the resolution of the device--particles with the wrong velocity will be accelerated away from the straight line and will not pass through the exit slit. If the acceleration depends strongly on the velocity, then particles with just slightly wrong velocities will feel a substantial transverse acceleration and will not exit the selector. Because the acceleration depends on the mass and charge, these influence the sharpness (resolution) of the transmitted particles.
Assume that you want a velocity selector that will allow particles of velocity v⃗ to pass straight through without deflection while also providing the best possible velocity resolution. You set the electric and magnetic fields to select the velocity v. To obtain the best possible velocity resolution (the narrowest distribution of velocities of the transmitted particles) you would want to use particles with __________.

a) both q and m large
b) q large and m small
c) q small and m large
d) both q and m small
Physics
1 answer:
valina [46]4 years ago
5 0

Answer:

The values of q must be large and m small to obtain the best possible velocity resolution (the narrowest distribution of velocities of the transmitted particles).

Explanation:

Based on Newton's law of motion, the formula for force is as below:

f = ma ---------------------------1

But a = a = v²/r

so, f = mv²/r -------------------2

Also, f = qE  --------------------3

From the equations above, it is observed that the values of q must be large and m small to obtain the best possible velocity resolution (the narrowest distribution of velocities of the transmitted particles).

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oksian1 [2.3K]

Answer:

10.2 lbs

Explanation:

m=F/g

m=100N/9.8

m=10.2040816 lbs

6 0
3 years ago
I need help on 2/3 please asap thx ♥️
ch4aika [34]

<u>questions 2</u>

F=m

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4 years ago
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Hitman42 [59]

<em>A clamp-type measuring instrument operates on the principle of; </em>

A. induction

8 0
3 years ago
During a plane showcase, a pilot makes circular "looping" with a speed equal to the sound speed (340 m/s). However, the pilot ca
Dmitriy789 [7]

Answer:

1472.98 m

Explanation:

Data provided:

Speed of circular looping, v = 340 m/s

Acceleration, a = 8g

here,

g is the acceleration due to the gravity = 9.81 m/s²

Now,

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on substituting the respective values, we get

8\times9.81=\frac{340^2}{r}

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5 0
4 years ago
A Carnot engine whose high-temperature reservoir is at 464 K has an efficiency of 25.0%. By how much should the temperature of t
nexus9112 [7]

Answer

given,

high temperature reservoir (T_c)= 464 K

efficiency  of reservoir (ε)= 25 %

temperature to decrease = ?

increase in efficiency = 42 %

now, using equation

 \epsilon = 1 - \dfrac{T_C}{T_H}

 0.25 = 1 - \dfrac{T_C}{464}

 T_C= (1 - 0.25) \times 464

 T_C= 0.75 \times 464

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now,

if the efficiency is equal to 42$ = 0.42

 T_C= (1 - 0.42) \times 464

 T_C= 0.58 \times 464

 T_C= 269.12\ K

8 0
3 years ago
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