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Mumz [18]
3 years ago
5

To get an idea of the order of magnitude of inductance, calculate the self-inductance in henries for a solenoid with 900 loops o

f wire wound on a rod 6 cm long with radius 1 cm?
Physics
1 answer:
Allisa [31]3 years ago
4 0

Answer:

The  self-inductance is  L =  0.0053 \ H

Explanation:

From the question we are told that  

      The number of loops is  N  =  900

      The  length of the rod is  l  =6 \ cm  = 0.06 \ m

      The radius of the rod is  r =  1 \ cm =  0.01 \ m

The  self-inductance for the solenoid is mathematically represented as

        L =  \frac{\mu_o  * A  *  N^2 }{l}

Now the cross-sectional of the solenoid is mathematically evaluated as

        A =  \pi r^2

substituting values  

         A =3.142 *   0.01 ^2

        A = 3.142 *10^{-4} \  m^2

and  \mu_o is the permeability of free space with a value  \mu_o  =   4\pi * 10^{-7} N/A^2

    substituting values into above equation

          L =  \frac{   4\pi * 10^{-7} ^2*  3.142*10^{-4}  *  900^2 }{0.06}

          L =  0.0053 \ H

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