D.Radiant energy does not require a medium through which to travel.
Answer:
ΔU= 1.3922 KJ
Explanation:
Given that
Q= 2 KJ
Note- 1 .Heat added to the system taken as positive and heat leaving from the system is taken negative.
2. Work done on the system taken as negative and work done by the system taken as positive.
P =2 atm
V₁= 2 L
V₂=5 L
Work done by the gas W
W= P ( V₂- V₁)
W= 2 ( 5 - 2)
W= 6 atm.L
1 L·atm = 0.1013 kJ
W= 0.6078 KJ
From first law of thermodynamics
Q= W + ΔU
ΔU=Change in internal energy
2 = 0.6078 + ΔU
ΔU= 1.3922 KJ
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Answer:
The electrical resistance of an object is a measure of its opposition to the flow of electric current.
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