Ask question

Ask question

All categories

2 years ago

11

The angular quantities L, omega, and alpha are vectors. The vectors point along the axis of rotation with a direction determined

by __________.

1 answer:

astra-53 [7]2 years ago

4 0

Answer:

Angular momentum and angular velocity have both magnitude and direction and, therefore, are vector quantities.

Explanation:

You might be interested in

Sam shared with his class that he lives on Oak Street. Sam is likely how old?

Lyrx [107]

D FOUR years old hope this helps

mark brainliest please

4 0

3 years ago

Read 2 more answers

Please provide the steps

elena-s [515]

Answer:

wA - T =mA(a)

second option

Explanation:

get step by step full answer from trusted experts

just join this wats up group

scan QR

post question

get step by step answer instantly

get good grade in exam

8 0

2 years ago

A rock is projected upward from the surface of the moon, at time t = 0.0 s, w a velocity of 30 m/s. The acceleration due to grav

Vinvika [58]

<h2>Answer: 277.777 m</h2>

Explanation:

The situation described here is parabolic movement. However, as we are told that the rock was<u> projected upward from the surface</u>, we will only use the equations related to the Y axis.

In this sense, the movement equations in the Y axis are:

$y-y_{o}=V_{o}.t+\frac{1}{2}g.t^{2}$ (1)

$V=V_{o}-g.t$ (2)

Where:

$y$ is the rock's final position

$y_{o}=0$ is the rock's initial position

$V_{o}=30\frac{m}{s}$ is the rock's initial velocity

$V$ is the final velocity

$t$ is the time the parabolic movement lasts

$g=1.62\frac{m}{s^{2}}$ is the acceleration due to gravity at the surface of the moon

As we know $y_{o}=0$ , equation (2) is rewritten as:

$y=V_{o}.t+\frac{1}{2}g.t^{2}$ (3)

On the other hand, the maximum height is accomplished when $V=0$ :

$V=V_{o}-g.t=0$ (4)

$V_{o}-g.t=0$

$V_{o}=g.t$ (5)

Finding $t$ :

$t=\frac{V_{o}}{g}$ (6)

Substituting (6) in (3):

$y=V_{o}(\frac{V_{o}}{g})+\frac{1}{2}g(\frac{V_{o}}{g})^{2}$ (7)

$y_{max}=\frac{{V_{o}}^{2}}{2g}$ (8) Now we can calculate the maximum height of the rock

$y_{max}=\frac{{(30m/s)}^{2}}{(2)(1.62m/s^{2})}$ (9)

Finally:

$y_{max}=277.777m$

4 0

3 years ago

If the mean velocity adjacent to the top of a wing of 1.8 m chord is 40 m/s and that adjacent to the bottom of the wing is 31 m/

Cloud [144]

Answer:

lift per meter of span = 702 N/m

Explanation:

See attached pictures.

7 0

3 years ago

How does the theory of plate tectonics support the theory of seafood spreading?

Zanzabum

When two tectonic plates move in opposite directions, it causes magma to rise, creating a new seafloor.

3 0

3 years ago