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3 years ago

11

The angular quantities L, omega, and alpha are vectors. The vectors point along the axis of rotation with a direction determined

by __________.

1 answer:

astra-53 [7]3 years ago

4 0

Answer:

Angular momentum and angular velocity have both magnitude and direction and, therefore, are vector quantities.

Explanation:

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A transformer with 1000 turns on the primary coil is used to decrease the voltage from 2500 V to 120 V for home use. How many tu

Katyanochek1 [597]

Answer:

The number of turns in the secondary coil is 48.

(B) is correct option.

Explanation:

Given that,

Number of turns on primary coil= 1000

Primary voltage = 2500 V

Secondary voltage = 120 v

We need to calculate the turns in the secondary coil

Using relation between voltage and number of turns in primary and secondary coil

$\dfrac{V_{s}}{V_{p}}=\dfrac{N_{s}}{N_{p}}$

Put the value into the formula

$\dfrac{120}{2500}=\dfrac{N_{s}}{1000}$

$N_{s}=\dfrac{120}{2500}\times1000$

$N_{s}=48\ turns$

Hence, The number of turns in the secondary coil is 48.

5 0

4 years ago

An object is traveling at 15 m/s and then after 5 seconds ends up traveling at 10 m/s. Calculate the speeds acceleration rate. W

SSSSS [86.1K]

Answer:

1) a = -1 m/s²

2) v = 12 m/s

Explanation:

Given,

The initial velocity of the object, u = 15 m/s

The final velocity of the object, v = 10 m/s

The time taken by the object to travel is, t = 5 s

Using the first equation of motion

<em>v = u + at</em>

a = (v - u) / t

Substituting the values

a = (10 - 15) / 5

= -1 m/s²

The negative sign indicates the body is decelerating

The acceleration of the object is, a = -1 m/s²

The speed of the object after 2 seconds

From the above equations of motion

v = 15 + (-1) 2

= 12 m/s

Hence, the speed of the object after 2 seconds is, v = 12 m/s

7 0

4 years ago

What is the Orbital Notation for Radon

balu736 [363]

I uploaded the answer to a file hosting. Here's link:

tinyurl.com/wpazsebu

4 0

3 years ago

a 1500 kg car accelerates uniformly from rest to 10.0 meters per secound in 3.0 secound .what is the work done on the car in thi

zubka84 [21]

Answer:

The work done on the car is, W = 75,000 J

The power delivered by the engine, P = 25,000 watts

Explanation:

Given,

The mass of the car, m = 1500 Kg

The initial velocity of the car, u = 0

The final velocity of the car, v = 10 m

The time duration of the travel, t = 3 s

Using the first equation of motion

v = u + at

a = (v - u) / t

Substituting the given values in the above equation

a = (10 - 0) / 3

= 3.33 m/s²

Using the second equations of motion

s = ut + 1/2 at²

= 0 + 0.5 x 3.33 x 3²

= 15 m

The force exerted by the car

F = m x a

= 1500 Kg x 3.33 m/s²

= 5000 N

The work done by the car,

W = F x S

= 5000 N x 15 m

= 75,000 J

Hence, the work done on the car is, W = 75,000 J

The power delivered by the engine,

P = W / t

= 75,000 J / 3 s

= 25,000 watts

The power delivered by the engine, P = 25,000 watts

5 0

4 years ago

Which correctly identifies the mass and approximate weight of the same object on Earth?

Vladimir79 [104]

Answer:

B.

Explanation:

w=mg

g=10m/s

hope this helps

4 0

3 years ago