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Margaret [11]
3 years ago
11

A body accelerates uniformly from rest at 2m/s square. calculate it's velocity after traveling 9m.​

Physics
1 answer:
Talja [164]3 years ago
3 0

Answer:

6m/s

Explanation:

Given parameters:

Initial velocity  = 0m/s

Acceleration  = 2m/s²

Distance  = 9m

Unknown:

Final velocity = ?

Solution:

To solve this problem, we use the expression below:

         v²  = u²  + 2as

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance

        v²   = 0² + (2 x 2 x 9) = 36

        v  = 6m/s

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A cricket starts at the 5 meter mark on a ruler. It jumps to the 10 meter mark. Then, it jumps back to the 6 meter mark. Calcula
belka [17]

We have that the cricket’s displacement is  

D_t=9meters

From the Question we are told that

Start position  5 meter mark

It jumps to the 10 meter mark.

it jumps back to the 6 meter mark.

Generally the equation for cricket’s displacement. is mathematically given as

D_t=Initial +final(displacement)\\\\D_t=(10-5)+(10-6)

D_t=9meters

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4 0
3 years ago
A student uses 150 N to push a block of wood up a ramp at constant velocity of 2.6m/s. What is his power output?
11Alexandr11 [23.1K]

Answer:

P= 390 W

Explanation:

In physics, power is the rate of doing work or of transferring heat, i.e. the amount of energy transferred or converted per unit time.  Work  is a force F applied over a distance x. Matemathicaly it means

P = dW/dt ≈ d(F * x)/dt = xdF/dt + Fdx/dt. If force is constant dF/dt=0 so P=F dx/dt = P*v, where v is velocity, the rate of distance per unit time.

We have force and velocity. Newton is unit of Kg*m/s2, hence

P= 150 kgm/s2 * 2.6 m/s =390 Kgm2/s3 = 390 W, where W is Watts and is an unit of power

8 0
3 years ago
HEY CAN ANYONE ANSWER DIS QUESTION PLS!!!!!!!!
Valentin [98]
It’s very big and very small numbers
6 0
3 years ago
Use the rules for significant figures to find the answer to the following addition problem: "21.4+15+17.17+4.003"
harina [27]

Answer:

57.6

Explanation:

"Significant figures" refer to figures that have an actual contribution to a <em>number's value.</em>

They refer to all digits<u> except those with</u><em><u> </u></em><em><u>"leading zero,"</u></em> which means having a zero digit before a specific number. For example, in the number 0234, the significant figures are<em> 234. </em>

The rule for adding and subtracting significant figures is to <em>round off the answer to the least number of decimal places</em>. However, when it comes to multiplying and dividing significant figures, you have<em> round off the answer to the least number of significant digits.</em>

<u>Let's solve.</u>

 21.4

+15

 17.17

<u>  4.003</u>

57.573

Let's now round off to the<em> least number of decimal places</em>, which is the <em>tenths. </em>Since 0.5 is followed by a number greater than 5, we have to round it off to 6. Therefore, the answer is: 57.6

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3 years ago
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