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adoni [48]
3 years ago
12

Which of the following expressions gives the amount of energy lost to friction by the toboggan and rider between points A and B?

Physics
1 answer:
motikmotik3 years ago
6 0

Answer:

The difference is the SI units used.

Explanation:

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A 50.0 kg driver is riding at 35.0 m/s in her red sports car when she must suddenly slam on the brakes to avoid
egoroff_w [7]

Answer:

3500N

Explanation:

Given parameters:

Mass of driver  = 50kg

Speed  = 35m/s

Time  = 0.5s

Unknown:

Average force the seat belt exerts on her = ?

Solution:

The average force the seat belt exerts on her can be deduced from Newton's second law of motion.

   F = mass x acceleration

So;

     F  = mass x  \frac{change in velocity }{time}

  F  = 50 x \frac{35}{0.5}    = 3500N

8 0
3 years ago
What is an invasive species plant??
lianna [129]
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6 0
3 years ago
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Arte-miy333 [17]

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7 0
3 years ago
Due to the earth's rotation, a person would be traveling faster at the equator than they would at a position halfway from the eq
Kisachek [45]

Answer:

False

Explanation:

It is actually the exact opposite.

8 0
3 years ago
Read 2 more answers
A student performs this experiment and measures the bar to have a mass of 150g and length of 36cm. What is the moment of inertia
Ugo [173]

Answer:

The moment of inertia of the bar is 45\times10^{-4}\ kg-m^2

Explanation:

Given that,

mass of bar = 150 g

Length l = 36 cm

We need to calculate the moment of inertia of the bar

Using formula of moment inertia

I=\dfrac{1}{12}Ml^2

Where,

M = mass of the bar

L = length of the bar

Put the value into the formula

I=\dfrac{1}{12}\times150\times10^-3\times36\times10^{-2}

I=45\times10^{-4}\ kg-m^2

Hence, The moment of inertia of the bar is 45\times10^{-4}\ kg-m^2

4 0
4 years ago
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