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Dimas [21]
4 years ago
9

A student performs this experiment and measures the bar to have a mass of 150g and length of 36cm. What is the moment of inertia

of the bar?
Physics
1 answer:
Ugo [173]4 years ago
4 0

Answer:

The moment of inertia of the bar is 45\times10^{-4}\ kg-m^2

Explanation:

Given that,

mass of bar = 150 g

Length l = 36 cm

We need to calculate the moment of inertia of the bar

Using formula of moment inertia

I=\dfrac{1}{12}Ml^2

Where,

M = mass of the bar

L = length of the bar

Put the value into the formula

I=\dfrac{1}{12}\times150\times10^-3\times36\times10^{-2}

I=45\times10^{-4}\ kg-m^2

Hence, The moment of inertia of the bar is 45\times10^{-4}\ kg-m^2

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mylen [45]

Answer:

The maximum magnetic force is 2.637 x 10⁻¹² N

Explanation:

Given;

Power, P = 8.25 m W = 8.25 x 10⁻³ W

charge of the radiation, Q = 1.12 nC = 1.12 x 10⁻⁹ C

speed of the charge, v = 314 m/s

area of the conecntration, A = 1.23 mm² = 1.23 x 10⁻⁶ m²

The intensity of the radiation is calculated as;

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The maximum magnetic field is calculated using the following intensity formula;

I = \frac{cB_0^2}{2\mu_0} \\\\B_0 = \sqrt{\frac{2\mu_0 I}{c} } \\\\where;\\\\c \ is \ speed \ of \ light\\\\\mu_0 \ is \ permeability \ of \ free \ space\\\\B_0 \ is \ the \ maximum \ magnetic \ field\\\\B_0 = \sqrt{\frac{2 \times 4\pi \times 10^{-7} \times 6,707.32 }{3\times 10^8} } \\\\B_0 = 7.497 \times 10^{-6} \ T

The maximum magnetic force is calculated as;

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5 0
3 years ago
Objects 1 and 2 attract each other with a electrostatic force of 18.0 units. If the charge
xxMikexx [17]

Answer:

new force is 6 times of the initial force.

Explanation:

Let the charges on two objects is q₁ and q₂. The electric force between charges is given by :

F=\dfrac{kq_1q_2}{r^2}

Objects 1 and 2 attract each other with a electrostatic force of 18.0 units

If the charge  of Object 1 is doubled and the charge of object 2 is tripled, it means, q_1'=2q_1 and q_2'=3q_2. New force is given by :

F'=\dfrac{kq_1'q_2'}{r^2}\\\\F'=\dfrac{k(2q_1)(3q_2)}{r^2}\\\\F'=6\dfrac{kq_1q_2}{r^2}\\\\F'=6F

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3 years ago
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givi [52]

Answer:

A. Both spheres land at the same time.

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Answer:

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Now, plug in the given values and solve for v.

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