Answer:
30.7 g of O₂ are produced
Explanation:
This is a redox reaction, where the peroxide is reduced to oxygen and oxidized to hydroxide. The equation is this one:
2Na₂O₂ + 2H₂O → 4NaOH + 3O₂
We assume that water is in excess, so the peroxide is the limiting reagent.
We convert the mass to moles: 50 g . 1mol / 78 g = 0.641 moles
2 moles of peroxide can produce 3 moles of oxygen (according to stoichiometry)
Then, 0.641 moles of peroxide will produce (0.641 . 3 ) /2 = 0.961 moles O₂
Finally, we convert the moles to mass: 0.961mol . 32 g / 1mol = 30.7 g of O₂
Answer:
Boiling point: 63.3°C
Freezing point: -66.2°C.
Explanation:
The boiling point of a solution increases regard to boiling point of the pure solvent. In the same way, freezing point decreases regard to pure solvent. The equations are:
<em>Boiling point increasing:</em>
ΔT = kb*m*i
<em>Freezing point depression:</em>
ΔT = kf*m*i
ΔT are the °C that change boiling or freezing point.
m is molality of the solution (moles / kg)
And i is Van't Hoff factor (1 for I₂ in chloroform)
Molality of 50.3g of I₂ in 350g of chloroform is:
50.3g * (1mol / 253.8g) = 0.198 moles in 350g = 0.350kg:
0.198 moles / 0.350kg = 0.566m
Replacing:
<em>Boiling point:</em>
ΔT = kb*m*i
ΔT = 3.63°C/m*0.566m*1
ΔT = 2.1°C
As boiling point of pure substance is 61.2°C, boiling point of the solution is:
61.2°C + 2.1°C = 63.3°C
<em>Freezing point:</em>
ΔT = kf*m*i
ΔT = 4.70°C/m*0.566m*1
ΔT = 2.7°C
As freezing point is -63.5°C, the freezing point of the solution is:
-63.5°C - 2.7°C = -66.2°C
A molecule has an empirical formula of ch, and its molar mass is known to be 26 g/mol and the molecular formula is C₂H₂ ethyne
Molecular formula of compound is (CH)n and the given molar mass is 26g/mol
Molar mass of (CH)n, C=12=n(12+1)=13n
So 13n and n=2
=13×2=26 and given molar mass is also 26g/mol
So here two carbon and two hydrogen so molecular formula is C₂H₂ and name is ethyne
Know more about molecular formula
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Answer:
It's the first option. A distance between two similar points on a wave of light.
Explanation:
On a wavelength chart, where you measure the rate at which the light travels at its distance from the source. You have two points to compare to.
Moles of ammonium sulfate = 26.42/molar mass of (NH4)2SO4
= 26.42/132.14 = 0.19 mole.
Molarity = moles of ammonium sulfate/volume of solution
= 0.19/50x10^-3
= 3.8M
