All categories

3 years ago

Which species acts exclusively as spectator ions in this reaction

Chemistry

1 answer:

adelina 88 [10]3 years ago

4 0

Answer:

K^+ and NO3^-

Explanation:

In a balanced ionic equation, we usually see the species that react to yield the main product in the reaction.

Consider the reaction;

Pb(NO3)2(aq) +2 KI(aq) -------> PbI2(s) + 2KNO3(aq)

The main product in this reaction is PbI2. Hence the balanced ionic equation is;

Pb^2+(aq) + 2I^-(aq) ------> PbI2(s)

Notice that K^+ and NO3^- did not participate in this reaction. All ions that are part of the molecular equation but do not participate in the ionic reaction equation are called spectator ions. Hence K^+ and NO3^- are spectator ions in this reaction as can be seen clearly above.

You might be interested in

During a storm, a tree fell over into a river. What might happen to this tree?

mina [271]

Break down in to tiny prices as the water hit the tree

6 0

3 years ago

Why will frequency decrease when wave gets longer

amid [387]

The frequency will decrease because the waves are getting farther and farther apart and if they and as that happens with shorter and shorter so they decrease

5 0

3 years ago

How many moles are in 2.98x10^23 particles?

Novosadov [1.4K]

Answer:

$\boxed {\boxed {\sf 0.495 \ mol}}$

Explanation:

We are given a number of particles and asked to convert to moles.

<h3>1. Convert Particles to Moles </h3>

1 mole of any substance contains the same number of particles (atoms, molecules, formula units) : 6.022 *10²³ or Avogadro's Number. For this question, the particles are not specified.

So, we know that 1 mole of this substance contains 6.022 *10²³ particles. Let's set up a ratio.

$\frac { 1 \ mol }{6.022*10^{23 } \ particles}}$

We are converting 2.98*10²³ particles to moles, so we multiply the ratio by that value.

$2.98*10^{23} \ particles *\frac { 1 \ mol }{6.022*10^{23 } \ particles}}$

The units of particles cancel.

$2.98*10^{23} *\frac { 1 \ mol }{6.022*10^{23 } }}$

$\frac { 2.98*10^{23}}{6.022*10^{23 } }} \ mol$

$0.4948522086 \ mol$

<h3>2. Round</h3>

The original measurement of particles (2.98*10²³) has 3 significant figures, so our answer must have the same.

For the number we found, 3 sig figs is the thousandth place.

The 8 in the ten-thousandth place (0.4948522086) tells us to round the 4 up to a 5 in the thousandth place.

$0.495 \ mol$

2.98*10²³ particles are equal to approximately <u>0.495 moles.</u>

3 0

3 years ago

If a substance is soluble in water, it will _______in water. A. settle B. float C. dissolve D. all of these

MrRa [10]

C.Dissolve because its another word for soluble

6 0

3 years ago

Read 2 more answers

Tellurium has eight isotopes: Te-120 (0.09%), Te-122 (2.46%), Te-123 (0.87%), Te-124 (4.61%), Te-125 (6.99%), Te-126 (18.71%), T

Elena-2011 [213]

The average atomic mass of tellurium, calculated from its eight isotopes (Te-120 (0.09%), Te-122 (2.46%), Te-123 (0.87%), Te-124 (4.61%), Te-125 (6.99%), Te-126 (18.71%), Te-128 (31.79%), and Te-130 (34.48%)) is 127.723 amu.

The average atomic mass of Te can be calculated as follows:

$A = m_{Te-120}\%_{Te-120} + m_{Te-122}\%_{Te-122} + m_{Te-123}\%_{Te-123} + m_{Te-124}\%_{Te-124} + m_{Te-125}\%_{Te-125} + m_{Te-126}\%_{Te-126} + m_{Te-128}\%_{Te-128} + m_{Te-130}\%_{Te-130}$

Where:

m: is the mass

%: is the abundance percent

Knowing all the masses and abundance values, we have:

$A = 120*0.09\% + 122*2.46\% + 123*0.87\% + 124*4.61\% + 125*6.99\% + 126*18.71\% + 128*31.79\% + 130*34.48\%$

To find the <u>average atomic mass</u> we need to change all the <u>percent values</u> to <u>decimal ones</u>

$A = 120*9 \cdot 10^{-4} + 122*2.46 \cdot 10^{-2} + 123*8.7\cdot 10^{-3} + 124*4.61 \cdot 10^{-2} + 125*6.99\cdot 10^{-2} + 126*0.1871 + 128*0.3179 + 130*0.3448 = 127.723$

Therefore, the average atomic mass of tellurium is 127.723 amu.

You can find more about average atomic mass here brainly.com/question/11096711?referrer=searchResults

I hope it helps you!

4 0

2 years ago