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3 years ago

Which species acts exclusively as spectator ions in this reaction

Chemistry

1 answer:

adelina 88 [10]3 years ago

4 0

Answer:

K^+ and NO3^-

Explanation:

In a balanced ionic equation, we usually see the species that react to yield the main product in the reaction.

Consider the reaction;

Pb(NO3)2(aq) +2 KI(aq) -------> PbI2(s) + 2KNO3(aq)

The main product in this reaction is PbI2. Hence the balanced ionic equation is;

Pb^2+(aq) + 2I^-(aq) ------> PbI2(s)

Notice that K^+ and NO3^- did not participate in this reaction. All ions that are part of the molecular equation but do not participate in the ionic reaction equation are called spectator ions. Hence K^+ and NO3^- are spectator ions in this reaction as can be seen clearly above.

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An atorn has 9 electrons and 9 protons at the start. If it loses 2 electrons, the net charge on the atom will be. If the atom in

LUCKY_DIMON [66]

Answer:

If it loses 2 electrons, the net charge on the atom will be 2+

If the atom instead gains 4 electrons, the net charge will be 4-

Explanation:

It is based on adding and subtracting charges. Protons are +1 and electrons are -1

If the atom has 9 protons and 9 electrons, the net charge is +9 + (-9) = 0. The +9 is the 9 protons and the -9 is from the 9 electrons.

If two electrons are taken away, there would be 9-2 or 7 electrons with 9 protons. The net charge would then be +9 + (-7) = +2. +9 comes from the 9 electrons and -7 is from the 7 electrons.

So, if two electrons are taken away, the net charge is +2.

Similarly, if the atom gains 4 electrons, there will be 9+4 or 12 electrons and 9 protons. The net charge would then be +9 + (-12) = -4. +9 comes from the 9 protons and -12 comes from the 12 electrons.

So, if 4 electrons are added, the net charge is -4.

3 0

3 years ago

What is the empirical formula for a compound if a sample contains 1. 0 g of S and 1. 5 g of O? SO SO3 S2O2 S2O3.

Tcecarenko [31]

The empirical formula of the given compound is $\bold{SO_3}$ .

The correct option is B.

<h3>What is an empirical formula?</h3>

The empirical formula of a chemical compound is the simplest whole-number ratio of atoms contained in the substance.

Given,

1.0 g of S

1.5 g of O

To calculate the empirical formula, we will divide the masses of the elements by their atomic weight.

For sulfur

$\bold{\dfrac{1.0}{32} =0.03125\; mol}$

For oxygen

$\bold{\dfrac{1.5}{16} =0.09375\; mol}$

Now, divide the greater value of mole came by the smaller value

$\bold{\dfrac{0.09375\; mol}{0.03125\;mol} = 3}$

Thus, the empirical formula for the given compound is 1 for S and 3 for O

$\bold{SO_3}$

Learn more about empirical formula, here:

brainly.com/question/11588623

7 0

2 years ago

Which of the following is not an indication of a chemical reaction?

eimsori [14]

Answer: Option (3) is the correct answer.

Explanation:

A reaction due to which there occurs change in chemical composition of reactants is known as a chemical reaction.

For example, evolution of heat when two substances combine together shows a chemical reaction has taken place between the substances.

Whereas a reaction which does not bring any changes in chemical composition of the reactants is known as a physical reaction.

For example, boiling point, melting point, mass, volume etc are all physical properties.

Thus, we can conclude that out of the given options a substance melts when sitting in the Sun, is not an indication of a chemical reaction.

7 0

4 years ago

Help me <br> Pleaseeeeeeeeeee

Fynjy0 [20]

It’s a synthesis reaction, which is when 2 or more substances react to form a single product.

I hope this helps

6 0

4 years ago

Suppose you were told that the above reaction was a substitution reaction but you were not told the mechanism. Evaluate the foll

Zarrin [17]

Answer:

The alkyl halide is secondary

The nucleophile is a poor nucleophile

The solvent is a protic solvent

The product is racemic

Explanation:

The reaction is shown in the image attached.

Alkyl halides undergo nucleophilic substitution by two mechanisms; SN1 and SN2. The particular mechanism that applies depends on;

I) structure of the alkyl halide

ii) nature of the nucleophile

iii) nature of the solvent

Looking at the reaction under review, we can see from the structure that the alkyl halide is a secondary alkyl halide. A secondary alkyl halide may undergo substitution via SN1 or SN2 mechanism depending on the conditions of the reaction.

If the nucleophile is poor, and the solvent is protic, SN1 mechanism is favoured over SN2 mechanism. Since CH3CH2OH is a poor nucleophile and ethanol is a protic solvent, we expect the reaction to proceed via SN1 mechanism leading to the formation of a racemic product.

The organic product is also shown in the second image attached.

3 0

3 years ago