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butalik [34]
3 years ago
12

In term of molecules explain what happen to a sugar cube when it is placed into a beaker of water

Chemistry
2 answers:
bazaltina [42]3 years ago
7 0
The sugar cube dissolves.<span />
Setler [38]3 years ago
5 0
The molecules in the sugar move from an area of higher concentration to an area of lower concentration in the water. ... They pick up molecules outside of the cell and bring them in.
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While ethanol (CH3CH2OH) is produced naturally by fermentation, e.g. in beer- and wine-making, industrially it is synthesized by
grin007 [14]

Answer:

n_{C2H_5OH}^{eq}=14.234mol

Explanation:

Hello,

In this case, the reaction is:

C_2H_4+H_2O\rightleftharpoons CH_3CH_2OH

Thus, the law of mass action turns out:

Kc=\frac{[CH_3CH_2OH]_{eq}}{[H_2O]_{eq}[CH_2CH_2]_{eq}}

Thus, since at the beginning there are 29 moles of ethylene and once the equilibrium is reached, there are 16 moles of ethylene, the change x result:

[CH_2CH_2]_{eq}=29mol-x=16mol\\x=29-16=13mol

In such a way, the equilibrium constant is then:

Kc=\frac{\frac{x}{V} }{\frac{16mol}{V}* \frac{3mol}{V}} =\frac{\frac{13mol}{75.0L} }{\frac{16mol}{75.0L}* \frac{3mol}{75.0L}} =20.31

Thereby, the initial moles for the second equilibrium are modified as shown on the denominator in the modified law of mass action by considering the added 15 moles of ethylene:

Kc=\frac{\frac{13+x_2}{V} }{\frac{16+15-x_2}{V}* \frac{3-x_2}{V}}  =20.31

Thus, the second change, x_2 finally result (solving by solver or quadratic equation):

x_2=1.234mol

Finally, such second change equals the moles of ethanol after equilibrium based on the stoichiometry:

n_{C2H_5OH}^{eq}=x+x_2=13mol+1.234mol\\n_{C2H_5OH}^{eq}=14.234mol

Best regards.

5 0
3 years ago
How many grams of NaOH would be needed to make 0.50 L of a 1.25 molar NaOH solution
Likurg_2 [28]

The solution would be made by dissolving 4 grams NaOH in .5 Liters of H2O
3 0
3 years ago
Susan conducts an experiment five times and gets a solution concentration of 1.9M, 2.1M, 1.8M, 1.9M, and 2.2M. The known concent
vlada-n [284]

Answer:

This question is incomplete; the complete part/options is:

A) They are precise, but not accurate.

B) They are accurate, but not precise.

C) They are both accurate and precise.

D) They are neither accurate nor precise

The answer is C.

Explanation:

Accuracy refers to how close a series of measurements is to a known or true value while precision is the closeness of the measurements to one another.

The known concentration of a solution is 2.0M. In an experiment which Susan conducts five times and gets a solution concentration of 1.9M, 2.1M, 1.8M, 1.9M, and 2.2M respectively.

Based on these measured solute concentrations, one would observe that the measured values of: 1.9M, 2.1M, 1.8M, 1.9M, 2.2M are close to one another. This means that the measurements are PRECISE.

Also, the measured values are not too distant from the known value of 2.0M, hence, it can be said that the measurements are ACCURATE.

Therefore, Susan's measurements of the solute concentration are both accurate and precise.

8 0
3 years ago
A mole of X reacts at a constant pressure of 43.0 atm via the reaction X(g)+4Y(g)→2Z(g), ΔH∘=−75.0 kJ Before the reaction, the v
hoa [83]

Answer:

The total energy change, ΔE, in kilojoules = -61.93 kJ

Explanation:

Relationship between ΔH, ΔE and work done is given by first law of thermodynamics.

ΔE = ΔH - PΔV

Where,

ΔH = Change in enthalpy

ΔE = Change in internal energy

PΔV = Work done

Given that,

ΔH = -75.0 kJ = -75000 J

P = 43.0 atm

ΔV = Final volume - initial volume

    = (2.00 - 5.00) = -3.00 L

PΔV = 43 × (-3.00) = -129 L atm

1 L atm = 101.325 J

-129 L atm = 129 × 101.325 = -13071 J

So ,

ΔE = ΔH - PΔV

     = (-75000 J) - ( -13071 J)

     =  -75000 J + 13071 J

     = -61929 J

Total energy change, ΔE = -61.929 kJ

3 0
3 years ago
What is chemistry,define it ?
AysviL [449]

Answer:

the branch of science that deals with the identification of the substances of which matter is composed; the investigation of their properties and the ways in which they interact, combine, and change; and the use of these processes to form new substances.

Explanation:

Hope this helps!

7 0
2 years ago
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