Answer:
<u>2</u>AgI + <u>1</u>Na₂S ⟶ <u>1</u>Ag₂S +<u>2</u>NaI
Explanation:
silver(I) iodide + sodium sulfide ⟶ silver(I) sulfide + sodium iodide
1. Convert the word equation to a chemical equation:
AgI + Na₂S ⟶ Ag₂S + NaI
2. Put a 1 in front of the most complicated-looking formula (Na₂S?):
AgI + <u>1</u>Na₂S ⟶ Ag₂S + NaI
3. Balance Na:
We have fixed 2 Na on the left. We need 2 Na on the right. Put a 2 in front of NaI.
AgI + <u>1</u>Na₂S ⟶ Ag₂S +<u>2</u>NaI
4. Balance S:
We have fixed 1 S on the left. We need 1 O on the right. Put a 1 in front of Ag₂S.
AgI + 1Na₂S ⟶ 1Ag₂S +2NaI
5. Balance Ag:
We have fixed 2Ag on the right. We need 2 Ag on the left. Put a 2 in front of AgI.
<u>2</u>AgI + <u>1</u>Na₂S ⟶ <u>1</u>Ag₂S +<u>2</u>NaI
Every formula now has a coefficient. The equation should be balanced.
6. Check that atoms balance:
<u>Atom</u> <u>On the left</u> <u>On the right
</u>
Ag 2 2
I 2 2
Na 2 2
S 1 1
The balanced equation is
<u>2</u>AgI + <u>1</u>Na₂S ⟶ <u>1</u>Ag₂S +<u>2</u>NaI
i believe the answer is D, please lmk if it is incorrect!
Potassium Recipients of massive transfusions may therefore develop electrolyte disturbances, with hypocalcemia, hypomagnesemia, and hyperkalemia most commonly reporte
Answer:
Explanation:
2N₂O(g) → 2N₂(g) + O₂(g)
molecular weight of N₂O = 44
∆Hº = –166.7 kJ/mol
44 g of N₂O decomposes to give 166.7 kJ of heat
2.25 g of N₂O decomposes to give 166.7 x 2.25 / 44 kJ of heat
= 8.51 kJ of heat .
