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lbvjy [14]
4 years ago
9

The theoretical yield of ammonia in an industrial synthesis was 550 kg, but only 480 kg was obtained. What was the percentage yi

eld of the reaction?
Chemistry
1 answer:
Klio2033 [76]4 years ago
7 0

We know that when calculating percent yield, we use the equation:


Percent yield=\frac{Actual yield (A)}{Theoretical yield (T)}


Since the quantities that we are given in the question are equal, we can just directly divide them to find percent yield:


Percentyield=\frac{480kg}{550kg} =0.8727*100=87.27


So now we know that the percent yield of the synthesis is 87.27%.

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3.0 L of a gas has a temperature of 78 C find the volume of the gas at standard temperature
jeka57 [31]

Answer:

= 2.33 L

Explanation:

V1/T1 = V2/T2

V1 = 3.0 L

T1 = 78 + 273

   = 351 K

At s.t.p the temperature is 273 K and pressure is 1 atm.

V2 = ?

T2 = 273 K

V2 = V1T2/T1

    = (3.0 ×273)/351

    = 2.33 L

Explanation:

ik it is confusing but that is what i got

4 0
3 years ago
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What is an example of a microorganism acting in a harmful way? A) Bacteria aiding digestion. B) Bacteria causing strep throat. C
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Which of the following became a major drawback to using ice blocks for cooling food? availability expense unsanitary ice storage
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7 0
4 years ago
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You have a 1.153 g sample of an unknown solid acid, HA, dissolved in enough water to make 20.00 mL of solution. HA reacts with K
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Answer:

The concentration of the unknown acid (HA) is 0.434M

The molar mass of HA is 13.3g/mole

Explanation:

DETERMINATION OF MOLARITY OF THE UNKNOWN ACID

CaVa/CbVb = Na/Nb

From the equation of reaction and at equivalence point, Na = Nb = 1

Therefore, CaVa = CbVb

Va (volume of acid solution) = 20mL = 20/1000 = 0.2L

Cb (concentration of KOH) = 0.715M

Vb (volume of KOH) = 12.15mL

Ca (concentration of acid) = CbVb/Va

Ca = 0.715M × 12.15mL/20mL = 0.434M

DETERMINATION OF MOLAR MASS OF HA

Number of moles of acid = concentration of acid × volume of acid solution in liters = 0.434 × 0.2 = 0.0868mole

Molar mass of HA = mass/number of moles = 1.153g/0.0868mole = 13.3g/mole

7 0
4 years ago
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swat32

Answer:

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