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PtichkaEL [24]
2 years ago
13

A student is given two 10g samples, each a mixture of only nacl(s) and kcl(s) but in different proportions. Which of the followi

ng pieces of information could be used to determine which mixture has the higher proportion of KCl(s) ?
A. The volume of each mixture
B. The mass of Cl in each mixture
C. The number of isotopes of Na and K
D. The reaction of each mixture with water
Chemistry
1 answer:
earnstyle [38]2 years ago
4 0

Answer:

a

Explanation:

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jek_recluse [69]

Answer:

Au. fifififiof

Explanation:

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3 years ago
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How much energy must be removed from a 94.4 g sample of benzene (molar mass= 78.11 g/mol) at 322.0 K to solidify the sample and
Kay [80]

Answer : The energy removed must be, 29.4 kJ

Explanation :

The process involved in this problem are :

(1):C_6H_6(l)(322K)\rightarrow C_6H_6(l)(279K)\\\\(2):C_6H_6(l)(279K)\rightarrow C_6H_6(s)(279K)\\\\(3):C_6H_6(s)(279K)\rightarrow C_6H_6(s)(205K)

The expression used will be:  

Q=[m\times c_{p,l}\times (T_{final}-T_{initial})]+[m\times \Delta H_{fusion}]+[m\times c_{p,s}\times (T_{final}-T_{initial})]

where,

Q = heat released for the reaction = ?

m = mass of benzene = 94.4 g

c_{p,s} = specific heat of solid benzene = 1.51J/g^oC=1.51J/g.K

c_{p,l} = specific heat of liquid benzene = 1.73J/g^oC=1.73J/g.K

\Delta H_{fusion} = enthalpy change for fusion = -9.8kJ/mol=-\frac{9.8\times 1000J/mol}{78g/mol}=-125.6J/g

Now put all the given values in the above expression, we get:

Q=[94.4g\times 1.73J/g.K\times (279-322)K]+[94.4g\times -125.6J/g]+[94.4g\times 1.51J/g.K\times (205-279)K]

Q=-29427.312J=-29.4kJ

Negative sign indicates that the heat is removed from the system.

Therefore, the energy removed must be, 29.4 kJ

3 0
3 years ago
¿Qué pasaría si un organismo o animal fuera eliminado de una red alimentaria?
34kurt

Answer: Sí

Explanation: Sí

4 0
3 years ago
A chemist measures the energy change ?H during the following reaction:
slamgirl [31]

Answer:

Endothermic

It absorbs heat

1.20 × 10³ kJ

Explanation:

Let's consider the following thermochemical equation.

2 H₂O(l) → 2 H₂(g) + O₂(g)    ΔH = 572 kJ

Since ΔH > 0, the reaction is endothermic, that is, it absorbs heat when H₂O reacts.

572 kJ are absorbed when 36.03 g of water react. The heat absorbed when 75.8 g of H₂O react is:

75.8 g H₂O × (572 kJ/36.03 g H₂O) = 1.20 × 10³ kJ

5 0
3 years ago
Please answer asap! worth 35 points!
Gnesinka [82]

Answer:

The enthalpy of the solution is -35.9 kJ/mol

Explanation:

<u>Step 1:</u> Data given

Mass of lithiumchloride = 3.00 grams

Volume of water = 100 mL

Change in temperature = 6.09 °C

<u>Step 2:</u> Calculate mass of water

Mass of water = 1g/mL * 100 mL = 100 grams

<u>Step 3:</u> Calculate heat

q = m*c*ΔT

with m = the mass of water = 100 grams

with c = the heat capacity = 4.184 J/g°C

with ΔT = the chgange in temperature = 6.09 °C

q = 100 grams * 4.184 J/g°C * 6.09 °C

q =2548.1 J

<u>Step 4:</u> Calculate moles lithiumchloride

Moles LiCl = mass LiCl / Molar mass LiCl

Moles LiCl = 3 grams / 42.394 g/mol

Moles LiCl = 0.071 moles

<u>Step 5:</u> Calculate enthalpy of solution

ΔH = 2548.1 J /0.071 moles

ΔH = 35888.7 J/mol = 35.9 kJ/mol (negative because it's exothermic)

The enthalpy of the solution is -35.9 kJ/mol

3 0
2 years ago
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