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Ratling [72]
3 years ago
8

What problems do you think might arise from not having a clear definition of "high crimes and misdemeanors"?

Physics
1 answer:
damaskus [11]3 years ago
6 0

Answer:

People might misunderstand it and problems might happen because the audience will have different opinions.

Explanation:

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Think of the last five things you read. Now think of a type of reading you havent done recenty
GarryVolchara [31]

Answer:

1) Half Girlfriend

2) I am Malala

3) Diamond fire

4)I too had a love story

5)Your Dream are Now Mine

Explanation:

I don't have a same pattern to read but mostly of romantic and fiction. I read less autobiographies but when I read I am Malala , it was an inspiring one.My favorite type of reading is romantic types and least favorite is non fiction especially History

6 0
3 years ago
Ozone, O3 methane, CH4 oxygen gas, O2 Are classified as
erma4kov [3.2K]
I would think compounds.
5 0
3 years ago
Read 2 more answers
Light of wavelength 600 nm passes though two slits separated by 0.22mm and is observed on a screen 1.1m behind the slits. The lo
Ne4ueva [31]

Answer:

y(m=1)=\frac{(1)(600*10^{-9}m)(1.1m)}{0.22m}=3*10^{-6}m\\\\y(m=1)=\frac{(-1)(600*10^{-9}m)(1.1m)}{0.22m}=-3*10^{-6}m

Explanation:

We have to take into account the expression for the position of the fringes

dsen\theta=m\lambda\\y=\frac{m\lambda D}{d}

where m is the number of the maximum, d is the separation of the slits, D is the distance to the screen.

(a) By replacing we obtain

y(m=1)=\frac{(1)(600*10^{-9}m)(1.1m)}{0.22m}=3*10^{-6}m\\\\y(m=1)=\frac{(-1)(600*10^{-9}m)(1.1m)}{0.22m}=-3*10^{-6}m

(b)  more information is required to solve this point. Please complete the information.

HOPE THIS HELPS!

4 0
3 years ago
Read 2 more answers
c. A car was running with a velocity of 20m/s. what will be its velocity after 30s if it's acceleration is 5m/s2​
weqwewe [10]

\large \mathfrak{Solution : }

let's use first equation of motion to solve this ;

  • \boxed{ \boxed{ v = u + at}}

  • v = 20 + (5 \times 30)

  • v = 20 + 150

  • v = 170 \:  \: m/s

Velocity after 30 seconds = 170 m/s

4 0
3 years ago
Two students are running down the hallway towards each other. Student 1 has a mass of 107kg and is running to the right at 4.1m/
antiseptic1488 [7]

Answer:

Hi

Explanation:

You are awesome

3 0
3 years ago
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