Answer:
6,2g of CO₂
Explanation:
Based on the reactions:
Li₂O(s) + H₂O(g) → 2LiOH(s)
LiOH(s) + CO₂(g) → LiHCO₃(s)
2,6g of Li₂O and 1,3g of H₂O are:
2,6g × ( 1mol / 29,88g) = 0,087 moles
1.3g × ( 1mol / 18,01g) = 0,072 moles
That means limiting reactant is H₂O. The moles produced of LiOH are:
0,072 moles of H₂O × ( 2mol LiOH / 1mol H₂O) =<em> 0,14 moles of LiOH</em>
Thus, the maximum CO₂ that can react are 0,14 moles of CO₂, in grams
0,14 moles CO₂ × (44,01g / 1mol) = <em>6,2g of CO₂</em>
I hope it helps!
