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2 years ago

What is (f*g)(x)? f(x)=x^4-9, g(x)=x^3+9

1 answer:

3 0

(x^4 - 9)(x^3 + 9)
This is a binomial * binomial. Use the FOIL method for multiplying.
First, outer, inner, last.
x^4 * x^3 = x^7
x°^4 * 9 = 9x^4
-9 * x^3 = -9 x^3
-9 * 9 = -81
Putting it back together.
x^7 +9x^4 -9x^3 - 81

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PLEASE HELP SUPER URGENT

Sveta_85 [38]

The equation for the table is f(x)=3x+1 so I don’t know for a but for b it would be f(x) because 1 is greater than 5.

6 0

2 years ago

If a = 7 and b = 11, what is the measure of ∠B? (round to the nearest tenth of a degree) A) 32.5° B) 39.2° C) 50.5° D) 57.5°

Ilia_Sergeevich [38]

Answer:

D) 57.5°

Step-by-step explanation:

As the question is not complete. So, let's suppose it is a right angle triangle then, we can apply Pythagoras theorem to calculate the hypotenuse or the third side.

Pythagoras Theorem = $c^{2}$ = $a^{2} + b^{2}$

a = 7 and b = 11

$a^{2}$ = 49

$b^{2}$ = 121

Plugging in the values, we will get:

$c^{2}$ = 49 + 121

$c^{2}$ = 170

c = $\sqrt{170}$

To calculate the unknown angle B, we can use law of sine.

Law of sine = $\frac{a}{sinA}$ = $\frac{b}{sinB}$ = $\frac{c}{sinC}$

So,

$\frac{c}{sinC}$ = $\frac{b}{sinB}$

$\frac{\sqrt{170} }{sin90}$ = $\frac{11}{sinB}$

Sin90 = 1

sinB = $\frac{11}{\sqrt{170} }$

B = $sin^{-1}$ ( $\frac{11}{\sqrt{170} }$ )

B = 57.5°

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2 years ago

An Arithmetic Sequence will yield a graph that is...

slava [35]

Answer:

A straight line.

Step-by-step explanation:

An arithmetic sequence has a common difference so the slope of the graph will be constant, giving a straight line.

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2 years ago

What is the surface area of the shape?

Sladkaya [172]

Answer:

Step-by-step explanation:

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2 years ago

Read 2 more answers

May someone help me out with this please. thanks

dmitriy555 [2]

Since your looking for the increase you can take the number from 2004
and 2014 and turn it into a fraction
54/135
now that you've done that times it by 100 like this

54/135 x 100=
40

and that will give you the percentile which is:
40%

Hope that helps X3

4 0

2 years ago