Answers: 1) 3 kg m²
2) 2.88 kg m²
Explanation: <u> </u><u>Question 1</u>
I = m(r)²+ M(r)²
I = 1.2 kg × (1 m )² +1.8 kg ×(1 m )²
∴ I = 3 kg m²
<u> </u><u>Question 2 </u>
ACCORDING TO THE DIAGRAM DRAWN FOR QUESTION 2
we have to decide where the center of gravity (G) lies and obviously it should lie somewhere near to the greater mass.<em> (which is 1.8 kg). S</em>ince we don't know the distance from center of gravity(G) to the mass (1.8 kg) we'll take it as 'x' and solve!!
<u>moments around 'G' </u>
F₁ d ₁ = F₂ d ₂
12 (2-X) = 18 (X)
24 -12 X =18 X
∴ X = 0.8 m
∴ ( 2 - x ) = 1.2 m
∴ Moment of inertia (I) going through the center of mass of two masses,
⇒ I = m (r)² +M (r)²
⇒ I = 1.2 × (1.2)² + 1.8 × (0.8)²
⇒ I = 1.2 × 1.44 + 1.8 × 0.64
⇒ I = 1.728 + 1.152
⇒ ∴ I = 2.88 kg m²
∴ THE QUESTION IS SOLVED !!!
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Missing question (found on internet):
"what is the force of the car?"
Solution:
According to Newton's second law, the force of the car is equal to the product between its mass and its acceleration:
For the car in the problem,
So the force that accelerates the car is
Answer:
16 Watts
Explanation:
P = VI, where V is the voltage and I is the current (of the lightbulb)
V = 8 volts, I = 2 amps
P = 8 * 2 = 16 Watts
Assuming constant acceleration <em>a</em>, the object has undergoes an acceleration of
<em>a</em> = (50 m/s - 100 m/s) / (25 s) = -2 m/s²
Then the net force has a magnitude <em>F</em> such that, by Newton's second law,
<em>F</em> = (75.0 kg) <em>a</em>
<em>F</em> = (75.0 kg) (-2 m/s²)
<em>F</em> = -150 N
meaning the object is acted upon by a net force of 150 N in the direction opposite the initial direction in which the object is moving.
A = horizontal displacement of the humming bird = 1.2 m
B = vertical displacement of the humming bird = 1.4 m
C = net displacement of the humming bird from initial to final position = ?
In the triangle drawn , Using Pythagorean theorem
C = √(A² + B²)
inserting the values
C = √(1.2² + 1.4²)
C = √(1.44 + 1.96)
C = √(3.4)
C = 1.4 m
Hence the net displacement of hummingbird comes out to be 1.4 m
