Answer:
0.00353J/g/°C
Explanation:
I will assume the temperature of the ice to be approximately 0°C.
Moreover, Heat of fusion of water is 6kJ
Amount of heat used to melt 5.3g of ice = 5.3 x 6 / 18
=1.767g°C
Therefore
1.767 = 25 x specific heat cap. x 200
Specific heat cap. = 1.767/(25x200)
= 0.00353J/g/°C
Please add you assignment.
Answer:
c. Histidine
Explanation:
Histidine is a compound that is normally used for the generation of protein. Three amino acids commonly have basic side chain when the pH is neutral. The conjugate acid in histidine has a pKa of approximately 6. Based on the description of the experimental analysis provided in the statement, the right option is option c.
The answer is: 1.5 moles of oxygen are present.
V(O₂) = 33.6 L; volume of oxygen.
p(O₂) = 1.0 atm; pressure of oxygen.
T = 0°C; temperature.
Vm = 22.4 L/mol; molar volume at STP (Standard Temperature and Pressure).
At STP one mole of gas occupies 22.4 liters of volume.
n(O₂) = V(O₂) ÷ Vm.
n(O₂) = 33.6 L ÷ 22.4 L/mol.
n(O₂) = 1.50 mol; amount of oxygen.
