Question

A 5.0 μf and a 7.0 μf capacitor are connected in series across an 8.0-v dc source. What is the voltage across the 5.0 μf capacitor?

Answer 1

Answer:4.67 V

Explanation:

Given

$C_1=5\ \muf$

$C_2=7\ \muf$

Voltage $V=8\ V$

For capacitance in series Net capacitance is given

$C_{net}=\frac{C_1\cdot C_2}{C_1+C_2}$

$C_{net}=\frac{5\times 7}{5+7}=\frac{35}{12} \muf$

$q=C_{net}V$

$q=\frac{35}{12}\times 8=\frac{70}{3} \muf$

As capacitors are in series so charge flow will be same in both capacitors

Voltage drop in $5 \muf$ capacitor

$V=\frac{70}{3}\times \frac{1}{5}=\frac{14}{3} V\approx 4.67 V$