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navik [9.2K]
3 years ago
8

Find acceleration. Will give brainliest!

Physics
2 answers:
Art [367]3 years ago
8 0

Answer:

\boxed{\mathrm{4.5 \: kmph/s \: or \: 1.25 \: m/s^2 }}

Explanation:

\displaystyle \mathrm{acceleration = \frac{change \: in \: velocity}{time \: taken}}

\displaystyle \mathrm{a = \frac{v - u}{t}}

\displaystyle \mathrm{v=final \: velocity}\\\displaystyle \mathrm{u=initial \: velocity}

\displaystyle \mathrm{a = \frac{45- 0}{10}}

\displaystyle \mathrm{a = \frac{45}{10}}

\displaystyle \mathrm{a = 4.5}

\mathrm{4.5 \: kmph/s = 1.25 \: m/s^2 }

zalisa [80]3 years ago
7 0

Answer:

16200 km/s

270 km/min

4.5 km/h

Explanation:

Acceleration Formula: Average Acceleration = Δv/Δt (change in velocity over change in time)

Simply plug in our known variables and solve:

a = (45.0 - 0)/10

a = 45.0/10

a = 4.5 km/h

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Answer: Hazmat products are allowed in your FC are:

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Explanation:

Hazmat products consist of flammable, corrosive and harmful substances which are actually very hazardous to human health and environment.  

Hazardous material allowed in FC are as follows.

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So, hazmat allowed products are GPS unit (lithium batteries) and subwoofer (magnetized materials).

Thus, we can conclude that hazmat products are allowed in your FC are:

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2 years ago
Two tugboats pull a disabled supertanker. Each tug exerts a constant force of 1.20×10^6 N, one at an angle 14.0∘ west of north,
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1.45544 J

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See attachment

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Nuclear Energy
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Answer:

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Explanation:

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2 years ago
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Tanzania [10]

Answer:

r = 0.05 m = 5 cm

Explanation:

Applying ampere's law to the wire, we get:

B = \frac{\mu_oI}{2\pi r}\\\\r =  \frac{\mu_oI}{2\pi B}

where,

r = distance of point P from wire = ?

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