Answer: Hazmat products are allowed in your FC are:
- A GPS unit (lithium batteries)
- A subwoofer (magnetized materials)
Explanation:
Hazmat products consist of flammable, corrosive and harmful substances which are actually very hazardous to human health and environment.
Hazardous material allowed in FC are as follows.
- Magnetized material products like as speakers.
- Non-spillable battery products like toy cars.
- Lithium-ion battery containing products like laptops, mobile phones etc.
- Non-flammable aerosol.
So, hazmat allowed products are GPS unit (lithium batteries) and subwoofer (magnetized materials).
Thus, we can conclude that hazmat products are allowed in your FC are:
- A GPS unit (lithium batteries)
- A subwoofer (magnetized materials)
A possible answer would be a stocker. a person who sorts thing or delivery person who just drops things off. there are little to no jobs with no human interaction. some good options for jobs where you work by yourself are:
<span>Embalmer.Accountant.Travel Photographer.Tree Planter.Freelance Writer.Truck Driver.Data Scientist.<span>Taxidermist. I HOPE THIS HELPS!!!</span></span>
Answer:
When uranium is mined, it consists of approximately 99.3% uranium-238 (U238), 0.7% uranium-235 (U235), and < 0.01% uranium-234 (U234). These are the different uranium isotopes. Isotopes of uranium contain 92 protons in the atom's center or nucleus. (The number of protons in the nucleus is what makes the atoms "uranium.") The U238 atoms contain 146 neutrons, the U235 atoms contain 143 neutrons, and the U234 atoms contain only 142 neutrons. The total number of protons plus neutrons gives the atomic mass of each isotope — that is 238, 235, or 234, respectively. On an atomic level, the size and weight of these isotopes are slightly different. This implies that with the right equipment and under the right conditions, the isotopes can be separated.
Explanation:
Answer:
r = 0.05 m = 5 cm
Explanation:
Applying ampere's law to the wire, we get:

where,
r = distance of point P from wire = ?
μ₀ = permeability of free space = 4π x 10⁻⁷ N/A²
I = current = 2 A
B = Magnetic Field = 8 μT = 8 x 10⁻⁶ T
Therefore,

<u>r = 0.05 m = 5 cm</u>