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Katena32 [7]
3 years ago
15

Mbbnmzmzkdjhxhxndmfmfmckcjcjcncncngmgkgjcjcj

Physics
2 answers:
Amiraneli [1.4K]3 years ago
8 0
Gmsisient djaektnfidiaus wjrnrksiauenrnsiaur msiwlwkrjsuakeurjrndkaiakejrjd laismrnff
likoan [24]3 years ago
6 0

Answer:

uxiakqoqkq81i101092ie9endndjdjd djdkpwp1pqmsoxkxoskwnnwkw

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Energy input remains constant and voltage remains the same in a circuit, but current decreases. Which must be happening?
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A) the resistance is increasing

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Which of the following statements about iron filings placed upon glass resting on top of a bar magnet is false?
leva [86]

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Which of the following values of pH will change blue litmus paper red?
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3 years ago
Acceleration refers to any changes in
Reptile [31]

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speed

Explanation:

6 0
2 years ago
The water stream strikes the inclined surface of the cart. Determine the power produced by the stream if, due to rolling frictio
levacccp [35]

Answer

given,

constant speed of cart on right side = 2 m/s

diameter of nozzle = 50 mm = 0.05 m

discharge flow through nozzle = 0.04 m³

One-fourth of the discharge flows down the incline

three-fourths flows up the incline

Power = ?

Normal force i.e. Fn acting on the cart

F_n = \rho A (v - u)^2 sin \theta

v is the velocity of jet

Q = A V

v = \dfrac{0.04}{\dfrac{\pi}{4}d^2}

v= \dfrac{0.04}{\dfrac{\pi}{4}\times 0.05^2}

v = 20.37 m/s

u be the speed of cart assuming it to be u = 2 m/s

angle angle of inclination be 60°

now,

F_n = 1000 \times \dfrac{\pi}{4}\times 0.05^2\times (20.37 - 2)^2 sin 60^0

F n = 2295 N

now force along x direction

F_x = F_n sin 60^0

F_x = 2295 \times sin 60^0

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Power of the cart

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P = 40.5 kW

3 0
3 years ago
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