Answer:
the magnetic field is leaving the sheet
Explanation:
The magnetic force is given by the expression
F = q v x B
where bold letters indicate vectors, the modulus of this expression is
F = q v B sin θ
the direction of the force is given by the right hand rule, for a positive charge
the thumb indicates the direction of the speed, in this case from right to left
the palm the direction of the force, in our case upwards
the fingers extended the direction of the magnetic field, this case after fixing the other two components it points out of the blade
In short the magnetic field is leaving the sheet
Answer:
v = 79.2 m/s
Solution:
As per the question:
Mass of the object, m = 250 g = 0.250 kg
Angle, 
Coefficient of kinetic friction, 
Mass attached to the string, m = 0.200 kg
Distance, d = 30 cm = 0.03 m
Now,
The tension in the string is given by:
(1)
Also
T = m(g + a)
Thus eqn (1) can be written as:





Now, the speed is given by the third eqn of motion with initial velocity being zero:

where
u = initial velocity = 0
Thus


Acceleration = Force \ mass
0,375N/0,60kg=0.6ms-2
kilograms or mass hope this helps