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lesya [120]
3 years ago
11

The general electron configuration for atoms of all elements in group 5a is

Chemistry
1 answer:
stiks02 [169]3 years ago
7 0
Well the elements would be N, P, As, Sb, and Bi. Their electron configuration would be N= [He] 2s2 2p3, P= 1s2 2s2 2p6 3s2 3p3, As= [Ar] 3d10 4s2 4p3, Sb=  Kr 4d10 5s2 5p3, and Bi= Xe 4f14 5d10 6s2 6p3.<span />
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Can someone help me on this
xz_007 [3.2K]
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I did this to the best of my ability. I have a hard time comprehending things sometimes so I’m so so so sorry if it’s wrong
8 0
2 years ago
How many moles of steam are produced when 5.74 moles of octane (C3H18) react?
jonny [76]

Answer:

51.66 mol H2O (steam)

Explanation:

5.74 mol C3H18 x 18 mol H2O/ 2 mol C3H18 = 51.66 mol H2O (steam)

6 0
2 years ago
ASAP LIKE RIGHT NOW<br> What is the frequency of a wave?
maw [93]

Answer:

The number of waves that pass a fixed point in a given amount of time

Explanation:

6 0
3 years ago
Read 2 more answers
Nicotine, a component of tobacco, is composed of c, h, and n. a 4.200-mg sample of nicotine was combusted, producing 11.394 mg o
Rudiy27

Answer:

            Empirical Formula  =  C₅H₇N₁

Solution:

Data Given:

                      Mass of Nicotine  =  4.20 mg  =  0.0042 g

                      Mass of CO₂  =  11.394 mg  =  0.011394 g

                      Mass of H₂O  =  3.266 mg  =  0.003266 g

Step 1: Calculate %age of Elements as;

                      %C  =  (mass of CO₂ ÷ Mass of sample) × (12 ÷ 44) × 100

                      %C  =  (0.011394 ÷ 0.0042) × (12 ÷ 44) × 100

                      %C  =  (2.7128) × (12 ÷ 44) × 100

                      %C  =  2.7128 × 0.2727 × 100

                      %C  =  73.979 %


                      %H  =  (mass of H₂O ÷ Mass of sample) × (2.02 ÷ 18.02) × 100

                      %H  =  (0.003266 ÷ 0.0042) × (2.02 ÷ 18.02) × 100

                      %H  =  (0.7776) × (2.02 ÷ 18.02) × 100

                      %H  =  0.7776 × 0.1120 × 100

                      %H  =  8.709 %


                      %N  =  100% - (%C + %H)

                      %N  =  100% - (73.979 % + 8.709%)

                      %N  =  100% - 82.688%

                      %N  =  17.312 %

Step 2: Calculate Moles of each Element;

                      Moles of C  =  %C ÷ At.Mass of C

                      Moles of C  = 73.979 ÷ 12.01

                     Moles of C  =  6.1597 mol


                      Moles of H  =  %H ÷ At.Mass of H

                      Moles of H  = 8.709 ÷ 1.01

                      Moles of H  =  8.6227 mol


                      Moles of N  =  %N ÷ At.Mass of O

                      Moles of N  = 17.312 ÷ 14.01

                      Moles of N  =  1.2356 mol

Step 3: Find out mole ratio and simplify it;

                C                                        H                                     N

            6.1597                               8.6227                             1.2356

     6.1597/1.2356                  8.6227/1.2356                 1.2356/1.2356

               4.985                             6.978                                   1

             ≈ 5                                      ≈ 7                                     1

Result:

        Empirical Formula  =  C₅H₇N₁

6 0
2 years ago
atch the following aqueous solutions with the appropriate letter from the column on the right. fill in the blank 1 A 1. 0.20 m N
Firdavs [7]

Answer:

Highest boiling point - 0.43 m Urea

Second highest boiling point - 0.20 m NiSO4

Third highest boiling point - 0.19 m NH4I

Lowest boiling point - 0.17 m NH4NO3

Explanation:

We know that;

ΔT = kb m i

Where;

ΔT = boiling point elevation

kb = boiling point constant

m = molality of the solution

i = Van't Hoff factor

For NiSO4 , NH4I  and NH4NO3 , the Van't Hoff factor, i = 2

But for Urea, the Van't Hoff factor, i = 1

We also have to consider both the values of the molality and Van't Hoff factor , knowing that a higher molality and a higher Van't Hoff factor leads to a higher ΔT and consequently a higher boiling point.

This facts above account for the arrangement of substances shown in the answer.

6 0
3 years ago
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