All categories

4 years ago

Question 1

Chemistry

1 answer:

luda_lava [24]4 years ago

4 0

Answer : The name of the given hydrocarbon is, pentane.

Explanation :

The basic rules for naming of organic compounds are :

First select the longest possible carbon chain.
For the number of carbon atom, we add prefix as 'meth' for 1, 'eth' for 2, 'prop' for 3, 'but' for 4, 'pent' for 5, 'hex' for 6, 'sept' for 7, 'oct' for 8, 'nona' for 9 and 'deca' for 10.
A suffix '-ane' is added at the end of the name of alkane.
If two of more similar alkyl groups are present, then the words 'di', 'tri' 'tetra' and so on are used to specify the number of times these alkyl groups appear in the chain.

In the given hydrocarbon, the longest possible carbon chain number is 5 that means we add prefix 'pent' and suffix '-ane'. So, the name of given hydrocarbon will be, pentane.

Hence, the correct option is, pentane.

You might be interested in

Define solubility. the amount of a substance that will dissolve in a given amount of solvent a solid mixed with another solid a

slavikrds [6]

Answer:

You answered your own question

5 0

3 years ago

What describes the likelihood that a given event will occur ?

attashe74 [19]

Answer

A: Probability

Explanation:

Please mark brainliest

6 0

3 years ago

Read 3 more answers

One gallon of gasoline in an automobiles engine produces on average 9.50 kg of carbon dioxide, which is a greenhouse gas; that i

vagabundo [1.1K]

Answer:

The value is $U =1.3908 *10^{11} \ kg$

Explanation:

From the question we are told that

mass of carbon dioxide produced by one gallon of gasoline is $m = 9.50 \ kg$

The number of cars is $N = 40 \ million = 40 *10^{6} \ cars$

The distance covered by each car is $d = 7930 \ mi$

The rate is $R = 23.6 \ mi/ gallon$

Generally the amount of gasoline used by one car is mathematically represented as

$G = \frac{d}{R}$

=> $G = \frac{7930}{23.6}$

=> $G = 366 \ gallons$

Generally the amount of gasoline used by N cars is

$H = N * G$

=> $H = 40*10^{6} * 366$

=> $H = 1.464*10^{10} \ gallons$

Generally the annual production of carbon dioxide is mathematically represented as

$U = m * H$

=> $U =9.50 * 1.464*10^{10}$

=> $U =1.3908 *10^{11} \ kg$

8 0

4 years ago

Caustic soda is 19.1 M NaOH and is diluted for household use. What is the household concentration if 10 mL of the concentrated s

olga nikolaevna [1]

Hello!

To calculate the household concentration of NaOH we need to use the dilution formula, clearing for M2, as you can see in the equation below:

$M1*V1=M2*V2 \\ \\ V2= \frac{M1*V1}{V2}$

Now, we input the values from the data we have onto this equation. M1=19,1 M; V1=10 mL; V2=400 mL, and solve the equation to get the result:

$V2= \frac{M1*V1}{V2}= \frac{19,1M*10mL}{400 mL}=0,48M$

So, the household concentration of NaOH will be 0,48 M

Have a nice day!

4 0

4 years ago

Nitric oxide, an important pollutant in air, is formed from the elements nitrogen and oxygen at high temperatures, such as those

Elden [556K]

Answer:

The Equilibrium will shift towards the left.

Explanation:

The reaction for the formation of nitric oxide is follows,

$N_2(g)+O_2(g)\leftrightarrow2NO(g)$

Expression for reaction quotient is as follows,

$Q=\frac{[NO]^2}{[N_2][O_2]}$

Putting the values according to the data given and calculating reaction quotient for the reaction

$Q=0.16$

So, the reaction quotient is 0.16.

and the value of K is 0.01 .

Q>K

Since the value of K is less than Q, therefore the reaction will shift towards left.

5 0

3 years ago