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mr Goodwill [35]
3 years ago
8

Density is an intensive physical property because the density of a given substance does not change with the size of the sample.

True or False
Chemistry
1 answer:
almond37 [142]3 years ago
6 0

True

Density = mass/volume

Suppose that a block has a mass of 20 g and a volume of 20 cm^3.

Density = 20 g/20 cm^3 = 1 g/cm^3

Now, you cut the block in half. The half-block has a mass of 10 g and a volume of 10 cm^3.

The density of the half-block is

Density = 10 g/10 cm^3 = 1 g/cm^3

The density <em>stays the same</em>, even though the size of the sample has changed.

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3. Which of the following substances is NOT an electrolyte? (1 point)
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Answer: electrolytes hydrate you and give you energy.

Explanation: please add more information to this question. I can tell you this though from my answer it should help you define what is and isn't an electrolyte. I hope that this is helpful to you.

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For the reaction PCl5(g) + heat PCl3(g) + Cl2(g), what will happen when the temperature is decreased
vovikov84 [41]
There will be a shift towards the reactants
5 0
3 years ago
Read 2 more answers
A geochemist in the field takes a 46.0 mL sample of water from a rock pool lined with crystals of a certain mineral compound X.
inysia [295]

Answer:

The solubility of the mineral compound X in the water sample is 0.0189 g/mL.

Explanation:

Step 1: Given data

The volume of water sample = 46.0 mL.

The weight of the mineral compound X after evaporation, drying, and washing = 0.87 g.

Step 2: Calculate the solubility of X in water

46.00 mL of water sample contains 0.87 g of the mineral compound X.

To calulate how many grams of the mineral compound  1.0 mL  of water sample contains:

0.87 g/46.0 mL = 0.0189 g.

This means the solubility of the mineral compound X in the water sample is 0.0189 g/mL.

3 0
3 years ago
The percent of remaining parent isotope in a radioactive decay process is 40 percent. How many half-lives have elapsed since the
muminat

Answer: Between 1 and 2.

Explanation:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

a=\frac{a_o}{2^n}        ............(1)

where,

a = amount of reactant left after n-half lives  = 40

a_o = Initial amount of the reactant  = 100

n = number of half lives

Putting in the values we get:

40=\frac{100}{2^n}  

2^n=2.5

taking log on both sides

nlog(2)=log(2.5)

n=1.32

Thus half-lives that have elapsed is between 1 and 2

7 0
3 years ago
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