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blondinia [14]
2 years ago
10

Determine the maximum height (in inches) that a lift pump can raise water (0.9971 g/ml) from a well at normal atmospheric pressu

re. Also present the cancellation of units to arrive at the final unit? Pls help. with solution​
Engineering
1 answer:
solniwko [45]2 years ago
7 0

Answer:Height = 30 inches​

Mass of water / Volume of water x Gravity constant for Earth x Density of Water. This cancels out to give us mass/volume, which is then cancelling mass, giving us the final unit of length/area (in this case inches).​

Explanation:

Height = 30 inches.

Units cancelled:

30/30 x 9.8 x 0.9971 = 30/39.97

The final units are in inches!​

2. Determine the weight (in pounds) that an ice cube at 32°F will displace when placed in water at 75°F.

Weight of ice cube / Volume of water x Gravity constant for Earth x Density of Ice = Weight displaced by ice cube in pounds​

Weight of ice cube / Volume of water x Gravity constant for Earth x Density of Ice = 0.5/75 x 32 x 0.92 = 0.5/22.67

The final units are in pounds!​

3. Determine the mass (in grams) of an ice cube at 32°F when placed in water at 75°F (assume no change in volume).

Mass of Ice Cube / Volume of Water x Gravity constant for Earth x Density of Ice = Mass of ice cube in grams

Mass of Ice Cube / Volume of Water x Gravity constant for Earth x Density of Ice = 0.5/75 x 32 x 0.92 = 15/22.67

The final units are in grams!​

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An inventor claims to have invented a heat engine that operates between the temperatures of 627°C and 27°C with a thermal effici
Oksana_A [137]

Answer Explanation:

the efficiency of the the engine is given by=1-\frac{T_2}{T_1}

where T₂= lower temperature

           T₁= Higher temperature

we have given efficiency =70%

lower temperature T₂=27°C=273+27=300K

higher temperature T₁=627°C=273+627=900K

efficiency=1-\frac{T_2}{T_1}

                =1-\frac{300}{900}

                 =1-0.3333

                 =0.6666

                 =66%

66% is less than 70% so so inventor claim is wrong

3 0
3 years ago
Electric heater wires are installed in a solid wall having a thickness of 8 cm and k=2.5 W/m.°C. The right face is exposed to an
Svet_ta [14]

Answer:

2.46 * 10⁵ W/m³

Explanation:

See attached pictures for detailed explanation.

6 0
3 years ago
Read 2 more answers
Steam enters an adiabatic turbine at 10 MPa and 500°C and leaves at 10 kPa with a quality of 90 percent. Neglecting the changes
Anna35 [415]

Answer:

The mass flow rate of steam m=5.4 Kg/s

Explanation:

Given:

  At the inlet of turbine P=10 MPa  ,T=500 C

 AT the exit of turbine  P=10 KPa   ,x=0.9

 Required power=5 MW

From steam table

<u> At 10 MPa and 500 C:</u>

  h=3374 KJ/Kg  ,s=6.59 KJ/Kg-K  (Super heated steam table)

<u>At 10 KPa:</u>

h_g=2675.1 KJ/Kg, h_f=417.51  KJ/Kg

s_g= 7.3  KJ/Kg-K                ,s_f=1.3   KJ/Kg-K

So enthalpy of steam at the exit of turbine

h= h_f+x(h_g- h_f)

Now by putting the values

h= 417.51+0.9(2675.1- 417.51) KJ/Kg

h=2449.34  KJ/Kg

Lets take m is the mass flow rate of steam

So 5\times 10^3=m\times (3374-2449.34)

m=5.4 Kg/s

So the mass flow rate of steam m=5.4 Kg/s

8 0
3 years ago
You are testing a new jet engine in a test cell at sea level conditions. You measure the mass flow through the engine and find i
bulgar [2K]

Answer:

43248 newtons.

Explanation:

Force = mass x accelerations and units of force are newtons which are given in the question.

here mass = 125 of air and 2.2 of fuel, total = 125+2.2=127.5kg/s  and the velocity of the exhaust is 340m/s.

force = 340m/s * 127.5kg/s = 43248 newtons technically this is wrong (observe units) but i will expalin how i have taken acceleration as a velocity here and mass/unit time as simply mass.

see force is mass times acceleration or deceleration, here our velocity is not changing therefore it is constant 340m/s but if it were to change and become 0 in one second then there would be -340m/s^2 (note the units ) of deceleration and there would be force associated with it and that force is what i have calculated here. similarly there would be mass in flow rate of mass per second, which is also in that one second of time.

let's calculate error.

error = (actual-calculated)/actual. = (43248-60000)/43248= -38.734% less is ofcourse greater than 2%.

So the load cell is not reading correct to within 2% and it should read 43248newtons.

5 0
2 years ago
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If a weld is laying into a joint with a concave weld contour with undercutting issues, what might be the cause?
Katarina [22]

Answer:bbbb

Explanation:

4 0
3 years ago
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