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3 years ago

14

The sun will probably end up as a white dwarf. How will it be different then from what it is today

1 answer:

just olya [345]3 years ago

6 0

Answer:

The differences that will be observed are;

1) The Sun will become faint and will no longer be yellow but rather appear white and will no longer be visible (become invisible) by unassisted vision as we can see the Sun today

2) The size of the Sun will shrink to a size comparable to the size of the Earth

3) The Sun will cool down and will no longer radiate as much heat

4) The nuclear reactions that generate energy on the Sun's will seize and the and the heat from the Sun will be from residual thermal energy

5) The core, which is the hottest part of the Sun will no longer be hydrogen but carbon and oxygen

Explanation:

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How thick is the Earth's surface?

marissa [1.9K]

It is typically 30 km to 50 km thick.

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4 years ago

Read 2 more answers

How can you determine the amount of work done on an object? (joules, work, power...etc.)

Novay_Z [31]

Work done is equal to force by distance; so you take the force exerted, in newtons, and multiply that by the direction it's moved (from the starting point in a line, not along the path it's taken.)

7 0

3 years ago

A motorcycle that is slowing down uniformly. The motorcycle covers 1 ????m=1000 m in 80 sec⁡. The motorcycle then covers the nex

Lynna [10]

Answer:

Part a)

acceleration = -0.042 m/s/s

Part b)

initial speed = 14.17 m/s

final speed = 5.77 m/s

Explanation:

Part a)

Let the initial velocity of the motorcycle is

$v_i = v_o$

now at the end of 80 s let the speed is

$v_f = v_1$

after another 120 s let the speed will be

$v_f' = v_2$

now we know that

$d = \frac{v_i + v_f}{2} (t)$

$d = \frac{v_o + v_1}{2}(80)$

$1000 = 40(v_o + v_1)$

also we know that

$v_1 - v_o = a(80)$

also we have

$1000 = \frac{v_1 + v_2}{2}(120)$

$1000 = 60(v_1 + v_2)$

now we can say

$(v_2 + v_1) - (v_o + v_1) = \frac{50}{3} - \frac{50}{2}$

also we know

$v_2 - v_o = a(120 + 80)$

$-8.33 = 200 a$

$a = -0.042 m/s^2$

Part b)

now we have

$v_1 + v_o = 25$

$v_1 - v_o = (-0.042)(80)$

$v_1 = 10.83 m/s$

so the starting velocity of the trip is

$v_o = 25 - 10.83 = 14.17 m/s$

now speed after t = 200 s is given as

$v_2 = v_o + at$

$v_2 = 14.17 - (0.042)(200)$

$v_2 = 5.77 m/s$

5 0

3 years ago

A force Fx=cx-3.00x2 acts on a virus as the virus moves along an x axis, with F measured in Newtons, x in meters, and c a consta

andrey2020 [161]

Answer:

4

Explanation:

We are given that

$F_x=cx-3x^2$

K.E at x=0 m=20 J

K.E at x=3 m=11 J

We have to find the value of c.

By work energy theorem

Work done=Change in kinetic energy

W= $\int_{0}^{3} Fdx=\int_{0}^{3}(cx-3x^2)dx$

$W=[\frac{cx^2}{2}-x^3]^{3}_{0}$

$W=\frac{9c}{2}-27$

$\Delta K=11-20=-9 J$

$-9=\frac{9c}{2}-27$

$-9+27=\frac{9c}{2}$

$18=\frac{9c}{2}$

$c=\frac{2}{9}\times 18=4$

4 0

4 years ago

a tractor pulls a wagon from rest with a constant force of 700 N eventually giving the wagon a speed of 20 km/h. how much work i

Semenov [28]

Work = Force × distance

We need to calculate distance travelled.

20km/hr = 20,000m / 60min → 333.3m/ min

333.3 × 3.5 min = 1,166.6 meters travelled

Force = 700 N and distance = 1,166.6 m

Work done is 700 N × 1,666.6 = 816,620 Nm

Power output = work /time

Power output is 816, 620 Nm / (3.5 × 60sec) →816, 620 / 210 = 3,888.7

Power output is 3,888.7 Watts.

Power output can also be expressed in joules per second so it is also correct to say work done is 3,888.7 J/s

5 0

3 years ago