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3 years ago

2 Points

Physics

1 answer:

posledela3 years ago

6 0

Answer:

A. Lever

Explanation:

A Lever is the kind of simple machine is the shin bone in your leg.

Hope this helps!

Feel free to ask if you have anymore questions!

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Tara prepared a report to show how the amplitude of waves affects the energy of waves. Is her graphical representation correct?

Gelneren [198K]

Answer:

It is not correct because the amplitude of the waves can be bigger than others and the graph can be going up and down

Explanation: I got the question right

6 0

3 years ago

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How strong is naruto i need a in depth answer going off his AP and DC i prefer powerscalers since they do this but anyone can an

marin [14]

Answer:

Naruto is kinda strong

Explanation:

If were just talking about just him I think that he is strong for letting go of his past and moving along with his life. Bu t he also isn't strong if you think about it if Naruto didn't have the nine tails he wouldn't be special so he also is not strong there for his only power really comes from the nine tails.

6 0

3 years ago

A circuit has a current of 3.6 A and a resistance of 5.0 Ω. What is the voltage applied to the circuit?

Inessa [10]

The key formula ===> Voltage = (current) x (resistance)

Plug in the numbers given ===> Voltage = (3.6 A) x (5.0 ohms)

Dooda multiplication ===> Voltage = 18 volts

7 0

2 years ago

Read 2 more answers

olivia is taking pictures of the ocean on the edge of a cliff when she accidentally drops her phone. The phone hits the water at

In-s [12.5K]

The cliff is 12.71m tall.

Why?

Before solving the problem, we must remember that the phone was dropped, it means that there is no initial velocity, also, the acceleration acting on the phone is the acceleration due to gravity.

So, to find how tall is the cliff, we can use the following equations:

$y=y_o+v_o*t-\frac{1}{2}g*t^{2}\\\\v_f=v_o+g*t$

$t=\frac{v_f}{g} \\\\t=\frac{-15.75\frac{m}{s}}{-9.81\frac{m}{s^{2}}}=1.61s$

Now that we know the time, we can calculate how tall is the cliff:

$y=y_o+v_o*t+\frac{1}{2}g*t^{2}\\\\y=0+0*1.61s-\frac{1}{2}*(-9.81\frac{m}{s^{2}})*(1.61s)^{2}\\\\y=12.71m$

Hence, we have that the cliff is 12.71m tall.

Have a nice day!

3 0

3 years ago

The cue ball is deflected so that it makes an angle of 30.0° with its original direction of travel.

Alexus [3.1K]

Answer:

(a) θ= 43.89°

(b) $v_{1} = 1.88\sqrt{3} \frac{m}{s}$

$v_{2} = 6.79 \frac{m}{s}$

Explanation:

Ball 1:

$u_{1} = 7.52\frac{m}{s}$

Ball 2:

$u_{2} = 0\frac{m}{s}$

As the collision is elastic, it means that kinetic energy and momentum are conserved. Following that, we apply the law of conservation of energy and momentum:

$\frac{1}{2} m_{1}u_{1}^{2} = \frac{1}{2} m_{1}v_{1}^{2} + \frac{1}{2} m_{2}v_{2}^{2}$

and

$m_{1}u_{1} = m_{1}v_{1} + m_{2}v_{2}$

Where u is the velocity before the collision, and v are the velocities after the collision. Both previous equations can be simplified as:

$u_{1}^{2} = v_{1}^{2} + v_{2}^{2}$

and

$u_{1} = v_{1} + v_{2}$

This because the two balls have the same mass. We know that the cue ball is deflected and makes an angle of 30°. From conservation in x-direction, we get::

$56.55 = v_{1} ^{2} + v_{2} ^{2}$

and

$u_{1} = v_{1}cos(30) + v_{2}cos(\theta)$

Solving we get:

$(\frac{2u_{1}-\sqrt{3}v_{1} }{2cos(\theta)})^{2} = 56.55-v_{1} ^{2}$

From conservation in y-direction, we get:

$0 = v_{1}sin(30) - v_{2}sin(\theta)$

From this, we solve this equation system and get the answers. Remember to add 30° to the angle obtained.

8 0

3 years ago