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Oxana [17]
3 years ago
6

a tractor pulls a wagon from rest with a constant force of 700 N eventually giving the wagon a speed of 20 km/h. how much work i

s done by the tractor in 3.5 min? whats the tractors power output?
Physics
1 answer:
Semenov [28]3 years ago
5 0


Work = Force × distance

We need to calculate distance travelled.

20km/hr = 20,000m / 60min  → 333.3m/ min

333.3 × 3.5 min = 1,166.6 meters travelled

Force = 700 N  and distance = 1,166.6 m

Work done is  700 N × 1,666.6 =  816,620 Nm

Power output = work /time

Power output is 816, 620 Nm / (3.5 × 60sec) →816, 620 / 210 = 3,888.7

Power output is 3,888.7 Watts.

Power output can also be expressed in joules per second so it is also correct to  say work done is 3,888.7 J/s

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A sound wave has a frequency of 250 Hz and a wavelength of 2.5 m. What is the speed of the wave?
Digiron [165]

ANSWER

625 m/s

EXPLANATION

Given:

• The frequency of the sound wave, f = 250 Hz

,

• The wavelength, λ = 2.5 m

Find:

• The speed of the wave, v

The speed of a wave of wavelength λ and frequency f is given by,

v=f\cdot\lambda

Substitute the known values and solve,

v=250Hz\cdot2.5m=625m/s

Hence, the speed of the wave is 625 m/s.

3 0
1 year ago
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4 0
3 years ago
A trombone plays a C3 note. If the speed of sound in air is 343 m/s and the wavelength of this note is
Umnica [9.8K]

The frequency of note C3 is 131 s^{-1}.

<u>Explanation:</u>

Frequency is the measure of repetition of same thing a certain number of times. So frequency is inversely proportional to the wavelength. As wavelength is distance between two successive crests or troughs in a sound wave.

And frequency is the completion of number of cycles in a given time in sound waves. The frequency and wavelength are inversely proportional to each other with velocity of sound being the proportionality constant.

Thus, here the speed of sound is given as 343 m/s, the wavelength of the note is also given as 2.62 m, then frequency will be as follows:

Frequency=\frac{speed of sound}{Wavelength of note}

Thus,

Frequency = \frac{343 m/s}{2.62 m} = 131 s^{-1}

So the frequency of note C3 is 131 s^{-1}.

3 0
2 years ago
What is the definition of chemical change
Dima020 [189]
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3 0
3 years ago
What is the car's speed at the bottom of the dip?The passengers in a roller coaster car feel 50% heavier thantheir true weight a
Rashid [163]

Answer:

v = 14 m/s

Explanation:

given,

radius of dip = 40 m

The passengers in a roller coaster car feel 50% heavier than their true weight.

Apparent weight

A = W + \dfrac{W}{2}

A =\dfrac{3W}{2}

A =\dfrac{3mg}{2}

When the car is at the bottom,  the weight will be acting downwards and the centripetal force will also be acting downward where as Normal force which is apparent weight will be acting in upward direction.

now,

N = m g + \dfrac{mv^2}{r}

\dfrac{3mg}{2} = m g + \dfrac{mv^2}{r}

\dfrac{mg}{2} = \dfrac{mv^2}{r}

v = \sqrt{\dfrac{rg}{2}}

v = \sqrt{\dfrac{40\times 9.8}{2}}

v = 14 m/s

8 0
2 years ago
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