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MAVERICK [17]
4 years ago
12

When Javier touches a hot mug of tea, energy is transferred from the surface of the mug to his hand. which kind of energy is thi

s?
Physics
1 answer:
disa [49]4 years ago
6 0
Heat Transfer. Heat transfer is the exchange of thermal energy between physical systems.
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A baseball is thrown 50.0m in 3.0s, what is the average speed of the baseball? Calculated answer is 16.666667! What is the corre
castortr0y [4]

Answer:

20m/s

Explanation:

Given parameters:

Distance of throw = 50m

Time  = 3s

Unknown:

Average speed  = ?

Solution:

Average speed is distance divided by time;

  Average speed  = \frac{distance }{time}

Insert the parameters and solve;

  Average speed  = \frac{50}{3}   = 16.66667m/s  = 20m/s

5 0
3 years ago
• List four uses of the concave mirror.<br> State five uses of lenses in everyday activities
Zina [86]
FOUR USES OF CONCAVE MIRROR:Satellite dishes,headlights of a car, telescopes used for astronomical studies, and shaving mirrors because of there curved and reflective surface.

FIVE USES OF LENSES: Camera lens ,microscopes ,magnifying glass,eyeglasses,projector
6 0
3 years ago
Why is the efficiency of a machine always less than 100 percent? The work input is too small. It cannot have an IMA greater than
kozerog [31]

Answer:

Some work input is lost to friction

Explanation:

The efficiency of a machine is defined as:

\eta = \frac{W_{out}}{W_{in}} (1)

where

W_{out} is the work output

W_{in} is the work input

Due to the law of conservation of energy, the work output can never be larger than the work input (because energy cannot be created). Moreover, in real machines part of the work input is lost due to the presence of frictions: as a result, part of the energy in input is converted into thermal energy or other forms of energy, and so the work output is smaller than the work input, and so the ratio (1) becomes less than 1, and so the efficiency is less than 100%.

3 0
3 years ago
Read 2 more answers
An airplane has a mass of 1.9E6 kg and the air flow past the
nordsb [41]

Answer:

v_{1}=164.4 m/s  

Explanation:

The Bernoulli equation is:

P+\frac{1}{2}\rho v^{2}+\rho gh=constant (1)

  • P is pressure related to the fluid
  • ρ is the density of the fluid (ρ(air)=1.23 kg/m³)
  • v is the speed of the fluid
  • h is the displacement from one position to the other

Now let's apply the equation (1), for our case:

P_{1}+\frac{1}{2}\rho v_{1}^{2}=P_{2}+\frac{1}{2}\rho v_{2}^{2} (2)

here we assume that h is the same in both cases so it canceled out.

  • <u>subscript 1</u> is related to the upper surface of the wings
  • <u>subscript 2</u> is related to the low surface of the wings

Solving the equation for v₁ we have:

v_{1}=\sqrt{\frac{2(P_{2}-P_{1})}{\rho}+v_{2}^{2}} (3)

Now, we know that pressure P=F/A (force over area)

\Dela P=\frac{W}{A}=\frac{mg}{A}=\frac{1.9\cdot 10^{6}\cdot 9.81}{1.6\cdot 10^{3}} =11649.4 N/m^{2} (4)

Combining (3) and (4), we can find v1.

v_{1}=\sqrt{\frac{2(11649.4)}{1.23}+90^{2}}  

v_{1}=164.4 m/s  

I hope it helps you!  

6 0
3 years ago
The gravitational force between two objects of masses m1 and m2 that are separated by distance r is...
strojnjashka [21]
Gravitational Force is F=G*m1*m2/r^2
7 0
3 years ago
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