Answer:15.2m/s
Explanation: Solution
Initial velocity(u)=6 meters per second
Final velocity(v)=?
Gravitational force (g) =9.8meter per second(square)
Height=10meters
Formula=
V(square)=u(square)+2*g(m/s(square)*height (m)
Velocity =√6(square)+√ 2*9.8*10
Velocity = √6*6+√2*9.8*10
Velocity= √36+√196
Velocity=√232
Velocity=15.2m/s.
This means that the man will be running at 15.2meters per second at the time he hits the ground. His final speed was increased because of the impact of the force of gravity (g).
Well the density is mass/volume
100/20 = 5
The density is 5
Answer:
Ff = u M g frictional force where u = .62
1/2 M v^2 kinetic energy of water bottle at release
Ff * d = 1/2 M v^2 = u M g d work to stop equals initial kinetic energy
v^2 = 2 u g d = 2 * .62 * 9.8 * 12 = 146 m^2 / s^2
v = 12.1 m/s
Answer
A force is a push or pull upon an object resulting from the object's interaction with another object.
Explanation:
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Answer:
9m^3
Explanation:
Given data
volume v1= 3m^3
volume v2= ???
Temperature T1= 20.0°C.
Temperature T2= 60.0°C.
Applying the relation for temperature and volume
V1/T1= V2/T2
substitute
3/20= V2/60
3*60= V2*20
180= 20*V2
180/20= V2
V2= 9m^3
Hence the final volume is 9m^3
