The density of the unknown material is 0.213 ml/g
<h3>
Apparent density of the unknown material</h3>
The apparent density of the unknown material is calculated as follows;
Volume of the unknown substance = 126 ml - 102 ml = 24 ml
Density of the unknown substance = mass/volume
Density of the unknown substance = 24 ml / 112.6 g
Density of the unknown substance = 0.213 ml/g
Thus, the density of the unknown material is 0.213 ml/g
Learn more about density here; brainly.com/question/6838128
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D. Cycloalkene
________________________
Answer : The equilibrium concentration of 
at 
is, 
.
Solution : Given,
Equilibrium constant, 
Initial concentration of 
= 0.260 m
Let, the 'x' mol/L of are formed and at same time 'x' mol/L of are also formed.
The equilibrium reaction is,
Initially 0.260 m 0 0
At equilibrium (0.260 - x) x x
The expression for equilibrium constant for a given reaction is,
![K_c=\frac{[H_3O^+][C_2H_3O_2^-]}{[HC_2H_3O_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BH_3O%5E%2B%5D%5BC_2H_3O_2%5E-%5D%7D%7B%5BHC_2H_3O_2%5D%7D)
Now put all the given values in this expression, we get
By rearranging the terms, we get the value of 'x'.
Therefore, the equilibrium concentration of at is, .
Explanation is in the file
tinyurl.com/wpazsebu
Answer:
1.54grams
Explanation:
Molarity of a solution = n/V
Where;
n = number of moles (mol)
V = volume (L)
Based on the information given in this question;
Volume of NaOH solution = 5.0 × 10ml
= 50ml = 50/1000 = 0.050 L
Molarity = 0. 77 M
Using; Molarity = n/V
0.77 = n/0.05
n = 0.77 × 0.05
n = 0.0385mol
To find the mass (grams) of NaOH in the solution, we use the following formula:
mole (n) = mass/molar mass
Molar mass of NaOH = 23 + 1 + 16 = 40g/mol
0.0385 = mass/40
mass = 0.0385 × 40
mass = 1.54grams.
