Answer:
vB = 8.57[m/s]
Explanation:
Since there is no external force that generates momentum, the amount of momentum is conserved so you will have the following equation
![m_{A}*v_{A}=m_{B}*v_{B}\\Where:\\m_{A}= 90[kg]\\v_{A}=10[m/s]\\m_{B}=105[kg]\\\\Therefore:\\\\v_{B}=\frac{m_{A}*v_{A}}{m_{B}}\\ v_{B}=\frac{90*10}{105}\\v_{B}=8.57[m/s]](https://tex.z-dn.net/?f=m_%7BA%7D%2Av_%7BA%7D%3Dm_%7BB%7D%2Av_%7BB%7D%5C%5CWhere%3A%5C%5Cm_%7BA%7D%3D%2090%5Bkg%5D%5C%5Cv_%7BA%7D%3D10%5Bm%2Fs%5D%5C%5Cm_%7BB%7D%3D105%5Bkg%5D%5C%5C%5C%5CTherefore%3A%5C%5C%5C%5Cv_%7BB%7D%3D%5Cfrac%7Bm_%7BA%7D%2Av_%7BA%7D%7D%7Bm_%7BB%7D%7D%5C%5C%20v_%7BB%7D%3D%5Cfrac%7B90%2A10%7D%7B105%7D%5C%5Cv_%7BB%7D%3D8.57%5Bm%2Fs%5D)
99.0km/h =27.5m/s (this is the initial speed)
The final speed is zero
The distance is 50.0m
Therefore you use the formula:
vfinal²=vinitial²+2ad
a=(vfinal²-vinitial²)/2d
= (0²-27.5²)/(2x50.0)
=-7.5625 or in correct sigdigs -7.56m/s²
Hope this helps!
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Here is the answer to your question
The emf is induced in the wire will be 1.56 ×10 ⁻³ V. The induced emf is the product of the magnetic field,velocity and length of the wire.
<h3>What is induced emf?</h3>
Emf is the production of a potential difference in a coil as a result of changes in the magnetic flux passing through it.
When the flux coupling with a conductor or coil changes, electromotive Force, or EMF, is said to be induced.
The given data in the problem is;
B is the magnitude of the magnetic field,= 5.0 ×10⁻⁵ T
V(velocity)=125 M/SEC
L(length)=25 cm=0.25 m
The maximum emf is found as;
E=VBLsin90°
E=125 × 5.0 × 10⁻⁵ ×0.25
E=1.56 ×10 ⁻³ V
Hence, the emf is induced in the wire will be 1.56 ×10 ⁻³ V
To learn more about the induced emf, refer to the link;
brainly.com/question/16764848
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