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Butoxors [25]
3 years ago
10

Monochromatic light with a wavelength of 6.4 E -7 meter passes through two narrow slits, producing an interference pattern on a

screen 4.0 meters away. The first order bright band lines are 2.0 E -2 meters away from the central bright maxima. What is the distance between the slits?
1.3 E -4 m
8.0 E -6 m
3.2 E -9 m
7.8 E3 m
Physics
1 answer:
seropon [69]3 years ago
8 0

Answer:

The distance between the slits is given by  1.3 × 10^{-4} m

Given:

\lambda = 6.4 \times 10^{-7} m

D = 4 m

y = 2 \times 10^{-2} m

m = 1

To find:

distance between slits, d = ?

Formula used:

y = \frac{m \times \lambda \times D}{d}

y = distance of first bright band from central maxima

D = distance between screen and source

d = distance between slits

\lambda = wavelength

Solution:

distance of first bright band from central maxima is given by,

y = \frac{m \times \lambda \times D}{d}

y = distance of first bright band from central maxima

D = distance between screen and source

d = distance between slits

\lambda = wavelength

Thus,

d = \frac{m \times \lambda \times D}{y}

d = \frac{1 \times 6.4 \times 10^{-7} \times 4 }{2 \times 10^{-2} }

d = 1.28 × 10^{-4}

d = 1.3 × 10^{-4} m

The distance between the slits is given by  1.3 × 10^{-4} m

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Answer:

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b)ΔV' = 10.2 V

Explanation:

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