2 years ago

A crane does 9,500 J of work to lift a crate straight up using a force of 125 N. How high does the crane lift the crate?

Physics

1 answer:

Bad White [126]2 years ago

7 0

Work is Force x Distance. 9500J=125N*d. d=9500J/125N=76m

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Brrunno [24]

Answer:

0.73m/s2

Explanation:

The speed at which the passengers move is the final speed of the plane

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What force must be used to do 224 joules of work on an object over a distance of 32 meters

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A 2190 kg car moving east at 10.5 m/s collides with a 3220 kg car moving east. The cars stick together and move east as a unit a

Bezzdna [24]

To solve this problem it is necessary to apply the concepts related to the conservation of the Momentum describing the inelastic collision of two bodies. By definition the collision between the two bodies is given as:

$m_1v_1+m_2v_2 = (m_1+m_2)V_f$

Where,

$m_{1,2}$ = Mass of each object

$v_{1,2}$ = Initial Velocity of Each object

$V_f$ = Final Velocity

Our values are given as

$m_1 = 2190Kg$

$v_1 =10.5m/s$

$m_2 = 3220kg$

$V_f = 4.74m/s$

Replacing we have that

$m_1v_1+m_2v_2 = (m_1+m_2)V_f$

$(2190)(10.5)+(3220)v_2 = (2190+3220)(4.74)$

$v_2 = 0.8224m/s$

Therefore the the velocity of the 3220 kg car before the collision was 0.8224m/s

8 0

3 years ago