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bixtya [17]
3 years ago
7

A crane does 9,500 J of work to lift a crate straight up using a force of 125 N. How high does the crane lift the crate?

Physics
1 answer:
Bad White [126]3 years ago
7 0
Work is Force x Distance.  9500J=125N*d.  d=9500J/125N=76m
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<span>and the halfback's momentum = 89 x 6.7 = 596.3 kg m/s east </span>


<span>After the tackle they move together with a momentum equal to the vector sum of their separate momentums b4 the tackle </span>

<span>The vector triangle is right angled: </span>

<span>magnitude of final momentum = √(977.5² + 596.3²) = 1145.034 kg m/s </span>

<span>so (115 + 89)v(f) = 1145.034 ←←[b/c p = mv] </span>

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<span>direction of v(f) is the same as the direction of the final momentum </span>

<span>so direction of v(f) = arctan (596.3 / 977.5) = N 31° E (to 2 sig figs) </span>


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